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ds: coordinate2

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ds: coordinate2 [#permalink] New post 30 Apr 2005, 15:46
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pls skingshow wor
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 [#permalink] New post 01 May 2005, 02:30
C)...

1) the slope can be 1 and 1 or 0 and 1, etc.. => insufficient

2) same as above => insufficient

1)+2) B and K is 1 and 0 or 0 and 1 => one line goes trough the origin with a slope of 1 and the other line is parallel to the x-axis with a slope of zero. the lines intersect in the neg/neg part of the coordinate. both legs are 1 and the hypothenuse is sqrt 2 and the angle is 45.
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Re: ds: coordinate2 [#permalink] New post 02 May 2005, 20:48
mirhaque wrote:
pls skingshow wor


given eqs

y = kx+B--------(1)
y = Bx+k--------(2)

Both eq are of form y = mX +C

where m is slope and C is the constant value

For (1) slope is k and for (2) it is B

Now we have a formula

Tan (angle between 2 lines ) = (|m1-m2|)/(|1+m1*m2|)

where m1 and m2 are slopes of the two lines....

So the answer is C
Re: ds: coordinate2   [#permalink] 02 May 2005, 20:48
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