Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 02 Jul 2016, 03:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# DS_divisibility m05 #36

Author Message
Director
Joined: 22 Aug 2007
Posts: 567
Followers: 1

Kudos [?]: 33 [0], given: 0

If a, b, and c are positive distinct integers, is (a/b)/c an [#permalink]

### Show Tags

10 Oct 2007, 00:40
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c
Intern
Joined: 02 Aug 2007
Posts: 36
Followers: 0

Kudos [?]: 25 [0], given: 0

### Show Tags

10 Oct 2007, 01:48
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b).
if c=2 and b=3, the result is not an integer.
if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

My ans. is E
Intern
Joined: 02 Aug 2007
Posts: 36
Followers: 0

Kudos [?]: 25 [0], given: 0

### Show Tags

10 Oct 2007, 01:52
ronneyc wrote:
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

Hi,

the equation can be rewritten as (ac/b).

Stat. 1 is not sufficient let's take a=1, b=3 and c=2 the result is not an integer. And if we take b=4 the result is an integer.

Stat. 2 gives us [(b+c)c]/b = b + (c²/b).
if c=2 and b=3, the result is not an integer.
if c=2 and b=4 the result is an integer => thus stat. 2 not sufficient

Combining 1 & 2 we have both cases (integer and non integer)

My ans. is E

I missed (a) in stat 1 ... take b=4 and a=6
VP
Joined: 09 Jul 2007
Posts: 1104
Location: London
Followers: 6

Kudos [?]: 95 [0], given: 0

### Show Tags

10 Oct 2007, 04:05
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B
1. doesnt give info about others
2. suff.

(a/b)/c=a/bc

(b+c)/bc

1/b+1/c

since b and c are disticnt positive integers and b is not equal to c
the expression cannot be an integer
VP
Joined: 09 Jul 2007
Posts: 1104
Location: London
Followers: 6

Kudos [?]: 95 [0], given: 0

### Show Tags

10 Oct 2007, 04:32
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

tricky.
tempting to say C but it is B i think.
Intern
Joined: 03 Mar 2006
Posts: 4
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

10 Oct 2007, 05:59
Ravshonbek wrote:
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B
1. doesnt give info about others
2. suff.

(a/b)/c=a/bc

(b+c)/bc

1/b+1/c

since b and c are disticnt positive integers and b is not equal to c
the expression cannot be an integer

Welldone Rav. Got B 2!
_________________

winnie

Senior Manager
Joined: 27 Aug 2007
Posts: 253
Followers: 1

Kudos [?]: 11 [0], given: 0

### Show Tags

10 Oct 2007, 08:40
Again late B
Intern
Joined: 15 Mar 2007
Posts: 45
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

10 Oct 2007, 10:39
IrinaOK wrote:
If a, b, and c are positive distinct integers, is (a/b)/c an integer?
c = 2
a = b + c

B.

Q: (a/b)/c = (a/bc)
S1: Insuff
S2: a = b+c ==> (b+c)/bc - is always a fraction for any set of distinct positive integers - Suff
Intern
Joined: 08 Feb 2014
Posts: 10
Followers: 0

Kudos [?]: 25 [2] , given: 2

### Show Tags

26 Jun 2014, 23:18
2
KUDOS
A: Insuff. Given a, b are distinct integers, a/b must be an even integer. a=4, b=1 - true. a=9, b=3 - false. Both, true & false possible. Hence, inconclusive.
B: On simplifying, given b, c are distinct integers, (1/b + 1/c) must be an integer. For any b,c where b <> c, this is false. Hence, conclusive.

Thus, B.
Re: DS_divisibility m05 #36   [#permalink] 26 Jun 2014, 23:18
Similar topics Replies Last post
Similar
Topics:
M05 #36 - DS 6 10 Dec 2009, 21:40
m05 #36 1 19 Nov 2009, 05:49
m05#36 2 31 Jul 2009, 10:28
6 M05 #4 21 24 Sep 2008, 10:57
26 m05 #22 28 21 Sep 2008, 11:08
Display posts from previous: Sort by

# DS_divisibility m05 #36

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.