I'd say D, too.
I think this is hard to very hard.
In order to do it, the plan would be to find the area of the triange, and subtract the little arc piece from it.
Once we have the radius, which is four, we know everything about the square, which has side 8, and the triangle would be 32.
But the question is still about the arc.
For that, we see that the angle of CAD is 45. Therefore, if we drew a line OT (T being where AC hits the circle) we'd have an arc, and the degrees would be double CAD, so AOT is 90 degrees.
If that's true, then we know everything. The area of the whole wedge from AOT is 1/4 the area of the circle (because the arc angle is 90) and we can figure out the area of the triangle AOT because it's a 45 45 90 triangle with side 4.
So the area of the little arc we're subtracting is the area of the whole wedge minus the area of the triangle. Since we can get that, we can get the whole thing.
Same goes for two. With the triangle area, we can work backwards to everything else.