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# DS - Percentage

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Manager
Joined: 12 Apr 2006
Posts: 221
Location: India
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Kudos [?]: 17 [0], given: 17

DS - Percentage [#permalink]  01 May 2009, 07:29
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Was kind of lost on this one. Please explain the method to solve this. TIA

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SVP
Joined: 17 Jun 2008
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Kudos [?]: 131 [1] , given: 0

Re: DS - Percentage [#permalink]  01 May 2009, 13:12
1
KUDOS
C.

In 1995, K = J + 2000

In 1998,
(1+p/100)*K = (1+p/100)J + 2440.

Combining thw two equations will give P.
Manager
Joined: 12 Apr 2006
Posts: 221
Location: India
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Kudos [?]: 17 [0], given: 17

Re: DS - Percentage [#permalink]  01 May 2009, 23:05
scthakur wrote:
C.

In 1995, K = J + 2000

In 1998,
(1+p/100)*K = (1+p/100)J + 2440.

Combining thw two equations will give P.

Thanks for explanation. Now it looks kinda easy.
Manager
Joined: 28 Jan 2004
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Location: India
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Kudos [?]: 9 [0], given: 4

Re: DS - Percentage [#permalink]  01 May 2009, 23:20
The equation has 3 variables K,J and P. We have a relation between K and J but not P. How can we solve for P? Can you pls. calculate P...
Manager
Joined: 12 Apr 2006
Posts: 221
Location: India
Followers: 1

Kudos [?]: 17 [0], given: 17

Re: DS - Percentage [#permalink]  02 May 2009, 00:35
mdfrahim wrote:
The equation has 3 variables K,J and P. We have a relation between K and J but not P. How can we solve for P? Can you pls. calculate P...

In 1995 K = J + 2000
K - J = 2000 ---------------------------(1)

In 1998 (1 + p/100)*K = (1 + p/100)*J + 2440

Take Jason salary to left which gives

(1 + p/100)*K - (1 + p/100)*J = 2440
(1 + p/100)*(K - J) = 2440 --------------------(2)

Now put value of K - J from from (1) in (2)

(1 + p/100)*2000 = 2440

Now there is only 1 variable and can be solved easily, but don't need to as this is DS problem.
Re: DS - Percentage   [#permalink] 02 May 2009, 00:35
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