hardaway7 wrote:

I am having trouble factoring problems that having something in front of the x^2

For example- how would I do this?

3x^2 - 8x -3 = 0

OG says (3x+1)(x-3)

But how do you figure that out quickly?!

a fail proof way to solve a problem of the type

ax^2+bx+c=0 is

x=-b+/-sqrt(b^2-4ac)

A simpler approach is to look at the actual values of ac and b (with the signs).

Then find two integers k1 and k2 such that k1+k2 = ac and k1k2=b.

In the present situation,

ac=-9 and b=-8. Thus, k1=-9 and k2 = 1

and we get

3x^2-9x+x-3=0 and problem solved.

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tusharvk