I am having trouble factoring problems that having something in front of the x^2
For example- how would I do this?
3x^2 - 8x -3 = 0
OG says (3x+1)(x-3)
But how do you figure that out quickly?!
a fail proof way to solve a problem of the type
A simpler approach is to look at the actual values of ac and b (with the signs).
Then find two integers k1 and k2 such that k1+k2 = ac and k1k2=b.
In the present situation,
ac=-9 and b=-8. Thus, k1=-9 and k2 = 1
and we get
3x^2-9x+x-3=0 and problem solved.