Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Jun 1111:00 AM EDT
-01:00 PM EDT
TTP GMAT OnDemand gives serious students 400+ hours of expert video instruction, the full TTP course, AI support, weekly office hours, and a 715+ score guarantee—all built for elite GMAT score improvement.
Jun 2207:30 PM EDT
-09:30 PM EDT
Master the GMAT with expert live instruction, a personalized study plan, and real-time support. Includes 40 hours of online classes plus 6 months of access to the TTP GMAT OnDemand video course. Class date: Mon/Wed June 22, 2026 →August 26, 2026
I saw a formula on this forum but forgot the entire formula and what it is for... can someone pls help me recollect... it looks like x1(y2-y3)+y1(x2-x3)......
Attachments
distance.JPG [ 34.87 KiB | Viewed 2146 times ]
16 Nov 2012, 22:37
Kudos
Bookmarks
Hero's Formula
There are several ways to find the area of a triangle. Four of the most useful cases are shown below
a, b, & c are known. This is known as "Heron's Formula".
area = sqrt( S(S-a)(S-b)(S-c) ) where S = 1/2 (a+b+c)
a, b, & C are known
area = 1/2 a b sin(C)
a, B, & C are known
area = a^2/2 sin(B)sin(C)/sin(B+C)
The vertices are known
area = 1/2( x1(y2-y3)+x2(y3-y1)+x3(y1-y2) )
https://www.unitmath.com/um/p/Examples/G ... Plane.html
There are several ways to find the area of a triangle. Four of the most useful cases are shown below
a, b, & c are known. This is known as "Heron's Formula".
area = sqrt( S(S-a)(S-b)(S-c) ) where S = 1/2 (a+b+c)
a, b, & C are known
area = 1/2 a b sin(C)
a, B, & C are known
area = a^2/2 sin(B)sin(C)/sin(B+C)
The vertices are known
area = 1/2( x1(y2-y3)+x2(y3-y1)+x3(y1-y2) )
https://www.unitmath.com/um/p/Examples/G ... Plane.html
17 Nov 2012, 08:06
Kudos
Bookmarks
thank you for the post.... but none in these gupta..... it has a numerator and a denominator.... for some coordinate geometry problem Bunuel posted a answer with explanation and calculation but some other chap posted a formula in the same page which is a lottttt easier.....
