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# From MitDavidDv: GMAT Quant-Math Question #2

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From MitDavidDv: GMAT Quant-Math Question #2 [#permalink]

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07 Apr 2011, 15:43
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Difficulty:

25% (medium)

Question Stats:

77% (01:35) correct 23% (00:25) wrong based on 87 sessions

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What is 2 2/3 - 1 1/4 divided by 1/2 - 1/6 ?

A. 17/36
B. 36/17
C. 17/6
D. 17/4
E. 51/4
[Reveal] Spoiler: OA
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Re: From MitDavidDv: GMAT Quant-Math Question #2 [#permalink]

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07 Apr 2011, 15:55
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MitDavidDv wrote:
What is 2 2/3 - 1 1/4 divided by 1/2 - 1/6 ?

A. 17/36
B. 36/17
C. 17/6
D. 17/4
E. 51/4

$$\frac{2\frac{2}{3}-1\frac{1}{4}}{\frac{1}{2}-\frac{1}{6}}=\frac{\frac{8}{3}-\frac{5}{4}}{\frac{1}{2}-\frac{1}{6}}=\frac{\frac{8*4-5*3}{12}}{\frac{6-2}{12}}=\frac{\frac{32-15}{12}}{\frac{4}{12}}=\frac{32-15}{4}=\frac{17}{4}$$

Ans: "D"
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Re: From MitDavidDv: GMAT Quant-Math Question #2 [#permalink]

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07 Apr 2011, 21:15
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2 2/3 - 1 1/4 = 8/3 - 5/4 = (32 - 15 )/12 = 17/12

1/2 - 1/6 = (3-1)/6 = 2/6 = 1/3

So 17/12/1/3 = 17/12 * 3 = 17/4

Answer - D
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Re: From MitDavidDv: GMAT Quant-Math Question #2 [#permalink]

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09 Apr 2011, 23:59
Solved mentally.
17/12/4/12 = 17/4
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Re: From MitDavidDv: GMAT Quant-Math Question #2 [#permalink]

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10 Apr 2011, 00:10
MitDavidDv wrote:
What is 2 2/3 - 1 1/4 divided by 1/2 - 1/6 ?

A. 17/36
B. 36/17
C. 17/6
D. 17/4
E. 51/4

(2-1), (2/3-1/4) so in mixed frac: 1 5/12 => 17/12 / 1/3 = 17/4.

Is this approach correct? or is it just a fluke?
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Re: From MitDavidDv: GMAT Quant-Math Question #2 [#permalink]

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10 Apr 2011, 00:49
jamifahad wrote:
MitDavidDv wrote:
What is 2 2/3 - 1 1/4 divided by 1/2 - 1/6 ?

A. 17/36
B. 36/17
C. 17/6
D. 17/4
E. 51/4

(2-1), (2/3-1/4) so in mixed frac: 1 5/12 => 17/12 / 1/3 = 17/4.

Is this approach correct? or is it just a fluke?

2 2/3 - 1 1/4 can be written as (2 + 2/3) - (1 + 1/4), so (2-1) + (2/3 - 1/4) = (1) + (5/12).
Earlier we converted mixed fraction to fractions, so we can do the reverse now i.e.
(1)(5/12)

Your approach is good.
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Re: From MitDavidDv: GMAT Quant-Math Question #2   [#permalink] 10 Apr 2011, 00:49
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# From MitDavidDv: GMAT Quant-Math Question #2

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