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Geometry 4

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Manager
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Geometry 4 [#permalink] New post 26 Sep 2009, 02:23
00:00
A
B
C
D
E

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(N/A)

Question Stats:

100% (02:31) correct 0% (00:00) wrong based on 1 sessions
Q.
If V is the volume of a cuboid of dimension x, y, z and A is its surface, then A/V will be equal to
1. x^2*y^2*z^2
2. ½( 1/xy + 1/ xz + 1/ yz)
3. ½ ( 1/x +1/y+1/z)

OA- 3
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Re: Geometry 4 [#permalink] New post 26 Sep 2009, 05:34
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Volume of it is equal to V= x*y*z
Area of it is equal to the sum of 6 regions on its surface. There are 2 surfaces with dimensions x and y, two with x and z and two with y and z.
So the area = A= 2*x*y+2*x*z+2*y*z
A/V= 2(xy+xz+yz)/xyz= 2(1/x+1/y+1/z).
It is like option c but not the same. Please control OA ;)
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Re: Geometry 4 [#permalink] New post 26 Sep 2009, 06:44
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virtualanimosity wrote:
Q.
If V is the volume of a cuboid of dimension x, y, z and A is its surface, then A/V will be equal to
1. x^2*y^2*z^2
2. ½( 1/xy + 1/ xz + 1/ yz)
3. ½ ( 1/x +1/y+1/z)

OA- 3


V = xyz
A = 2 (xy + yz + zx)

A/V= 2(xy+yz+zx) / xyz = 2(1/x + 1/y + 1/z)

If question were what is V/A, then
V/A = xyz / [2(xy+yz+zx)] = 1 / [2 (1/x + 1/y + 1/z)]

In the given answer choices, if u put a extra bracket in the answer choice 3, then that will match with V/A.

_________________

:good Salaries are low in recession. So, working for kudos now. :good

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Manager
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Re: Geometry 4 [#permalink] New post 26 Sep 2009, 10:21
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Area = 2xy + 2yz + 2xz
Volume = xyz
Thus A/V = 2((xy + yz + xz)/xyz)
which is the same as
A/V = 2(1/x + 1/y + 1/z)
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Re: Geometry 4 [#permalink] New post 26 Sep 2009, 10:31
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area = 2(xy+yz+xz)
volume = xyz

A/V = 2(xy+yz+xz) / xyz = 2 (1/x+1/y+1/z)

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Bhushan S.
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Re: Geometry 4 [#permalink] New post 13 Oct 2009, 22:25
virtualanimosity wrote:
Q.
If V is the volume of a cuboid of dimension x, y, z and A is its surface, then A/V will be equal to
1. x^2*y^2*z^2
2. ½( 1/xy + 1/ xz + 1/ yz)
3. ½ ( 1/x +1/y+1/z)

OA- 3


OA cannot be 3. A/V will be 2( 1/x +1/y+1/z)

What is the source of this question?
Re: Geometry 4   [#permalink] 13 Oct 2009, 22:25
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