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Gmat Prep- Triangles

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Gmat Prep- Triangles [#permalink] New post 11 Jul 2006, 20:11
Ok, need some help. problem appeared on second gmat prep test

two triangles. the area of the triangle on the right (call her t1) is twice the area of that on the left (call him t2). In terms of b1, b2 equals....
area of triangle= 1/2 bh
the correct answer is (sqrt2) (b1), but i have no clue how they got it and am creating major voodoo. thanks, guys!

dg
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 [#permalink] New post 11 Jul 2006, 21:03
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The 2 triangles are proportional, which means that the ratios of respective sides of triangle are equal.
Lets assume the sides of smaller triangle a, b, c. The sides of a bigger one is A, B, C respectively.
since they are proportional, a/A=b/B=c/C=> A=x*a, B=x*b, C=x*c
the area of small triangle is 1/2a*b*sin(Y)
the area of big triangle is 1/2A*B*sin(Y)=a*b*sin(Y)=>A*B=2a*b=>
x*a*x*b=2a*b ----> x^2ab=2ab --->x=sqrt(2).
  [#permalink] 11 Jul 2006, 21:03
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Gmat Prep- Triangles

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