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# Gmatprep - computer chips

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Intern
Joined: 04 Feb 2007
Posts: 29
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Gmatprep - computer chips [#permalink]  04 Feb 2007, 10:40
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OA: B
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Senior Manager
Joined: 04 Jan 2006
Posts: 280
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Kudos [?]: 20 [0], given: 0

Expected Ratio = total defect from S1 to S4 / total Shipment
= (2 + 5 + 6 + 4)/(5k + 12k + 18k + 16K)

= 17/51k

if ship 60k, the defective part should be = 60k x 17/51k = 60/3 = 20 parts

Manager
Joined: 10 Dec 2005
Posts: 112
Followers: 1

Kudos [?]: 3 [0], given: 0

Defect / Total = Sum (defect) for each shipment / Sum (Total) for each shipment.

Hence,

D/T = 1/1000*(2+5+6+4 / 16+18+12+5) = 17/51,000 = 1/3,000

Now we know the next shipment is 60,000

D = 60,000 / 3,000 = 20
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