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23 Dec 2006, 07:23
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Please see attached.
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23 Dec 2006, 21:01
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Very interesting question but I think the answer is 3/8
Row 2 has two positions left and right so prob. of being in left = right = 1/2
Row 3 has three positions, probability of ending up in left = 1/4, in right = 1/4 and in middle = 1/4 + 1/4 = 1/2
Now for row 4 probabiity of ending up in cell 1 is 1/8, in cell 2 is 1/8 (note in this case it came in cell 2 afer being in positon on left on row 3)
if it goes in middle in row 3 first, prob of ending in cell 2 = 1/4, cell 3 = 1/4
if it goes right, prob of ending in cell 3 = 1/8, in cell 4 =1/8
Overall prob of ending in cell 2 = 3/8
Row 2 has two positions left and right so prob. of being in left = right = 1/2
Row 3 has three positions, probability of ending up in left = 1/4, in right = 1/4 and in middle = 1/4 + 1/4 = 1/2
Now for row 4 probabiity of ending up in cell 1 is 1/8, in cell 2 is 1/8 (note in this case it came in cell 2 afer being in positon on left on row 3)
if it goes in middle in row 3 first, prob of ending in cell 2 = 1/4, cell 3 = 1/4
if it goes right, prob of ending in cell 3 = 1/8, in cell 4 =1/8
Overall prob of ending in cell 2 = 3/8
23 Dec 2006, 22:14
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is the answer 1/8... ??
prob of going left or right is 1/2, which mean it is equally likely to go any way..
so the question boils down to finding the number of way one can reach to 2, (which are 3) vs total number of ways to reach down (which are 24)...
hence answer 3/24 = 1/8...
prob of going left or right is 1/2, which mean it is equally likely to go any way..
so the question boils down to finding the number of way one can reach to 2, (which are 3) vs total number of ways to reach down (which are 24)...
hence answer 3/24 = 1/8...
