Graph : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 20 Jan 2017, 20:34

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Graph

Author Message
Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India
Followers: 1

Kudos [?]: 37 [0], given: 0

Show Tags

11 Jul 2004, 17:58
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

(I do not know the method to upload the way BHAI does.) Can someone edit this and show the graph, instead of the download option). Or perhaps, let me know how to show the graph on the screen.

Thanks
Attachments

graph.doc [29 KiB]

_________________

Giving another SHOT

Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India
Followers: 1

Kudos [?]: 37 [0], given: 0

Show Tags

11 Jul 2004, 19:12
Hi

_________________

Giving another SHOT

Director
Joined: 05 May 2004
Posts: 577
Location: San Jose, CA
Followers: 2

Kudos [?]: 59 [0], given: 0

Show Tags

11 Jul 2004, 19:34
The diagram is not so clear and not to scale.

Anyways here's my approach:
Eq of a parabola with vertex at (x0,y0) is
(y-y0)^2=4a(x-x0)^2 (x,y) any pint on the parabola. 4a is called the latus rectum (it is just a constant)

Based on the diagram looks like the parabola passes thru (0,3)
vertex of the parabola here is (2,0)

Using this we get

9=4a*4
or a=9/16

hence eq is (y)^2 = 9/4 * (x-2)^2
when, x=3 y=3/2=1.5

This is the answer I get, though its not in the answer choice.

Did I commit any mistake?
Senior Manager
Joined: 25 Dec 2003
Posts: 359
Location: India
Followers: 1

Kudos [?]: 37 [0], given: 0

Show Tags

11 Jul 2004, 19:44
Hello Vijay

thanks man. I really do not know how to solve this. this question came from a frnd of mine in china. He says the OA is (-1/2). No idea, how that is. Perhaps, the OA is wrong or may be it needs a different approach.

Thanks mate
_________________

Giving another SHOT

Director
Joined: 05 May 2004
Posts: 577
Location: San Jose, CA
Followers: 2

Kudos [?]: 59 [0], given: 0

Show Tags

11 Jul 2004, 19:54
-1/2 is imposs
Just looking at the graph you can tell that
Intern
Joined: 07 Jul 2004
Posts: 42
Followers: 0

Kudos [?]: 28 [0], given: 0

Show Tags

12 Jul 2004, 08:01

From the shape of the function we know its type: y=a*(x+b)^2

Since 0=a*(2+b)^2 ==> b=-2

Since y is little less than 3 for x=0

3>4a
a>3/4

If x = 3
y>3/4*(3-2)^2 ==> y is little more than Â¾.
Intern
Joined: 07 Jul 2004
Posts: 42
Followers: 0

Kudos [?]: 28 [0], given: 0

Show Tags

12 Jul 2004, 08:33

should be a<3/4

If x =3

y<3/4*(3-2)^2 ==> y is between Â½ and Â¾. The answer is D
Senior Manager
Joined: 01 May 2004
Posts: 336
Location: USA
Followers: 3

Kudos [?]: 103 [0], given: 0

Show Tags

12 Jul 2004, 12:00
I've looked at the pic. It's obvious that y can be only positive, so then scan answer choices. Between 1 and 1/2, 1/2 suits better.
But formally, you would have write down eq. y=ax^2+bx+c, then by using given points find coefficients a, b and c.
SVP
Joined: 16 Oct 2003
Posts: 1810
Followers: 4

Kudos [?]: 136 [0], given: 0

Show Tags

12 Jul 2004, 13:19
carsen wrote:

(I do not know the method to upload the way BHAI does.) Can someone edit this and show the graph, instead of the download option). Or perhaps, let me know how to show the graph on the screen.

Thanks

There you go Carsen.
Attachments

Carsen.JPG [ 14.31 KiB | Viewed 1148 times ]

SVP
Joined: 16 Oct 2003
Posts: 1810
Followers: 4

Kudos [?]: 136 [0], given: 0

Show Tags

12 Jul 2004, 13:25
carsen wrote:

(I do not know the method to upload the way BHAI does.) Can someone edit this and show the graph, instead of the download option). Or perhaps, let me know how to show the graph on the screen.

Thanks

There you go Carsen.
Attachments

Carsen.JPG [ 14.31 KiB | Viewed 1147 times ]

Intern
Joined: 11 Jul 2004
Posts: 5
Followers: 0

Kudos [?]: 0 [0], given: 0

Show Tags

12 Jul 2004, 17:58
E... and I just eyeballed it.
_________________

my babbling: alexmba.blogspot.com
"Everybody needs money! That's why they call it money!" -- Mickey Bergman in "Heist"

12 Jul 2004, 17:58
Display posts from previous: Sort by