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Hard permutation/combination question

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Hard permutation/combination question [#permalink] New post 31 Oct 2003, 14:31
here is the question:
8 points lie on an xy plane. No more than 2 lie on the same line. How many triangles can you form with these points?

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leon
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 [#permalink] New post 01 Nov 2003, 03:49
you need to clarify this question. Are the triangles to be formed only with the given points as vertices? (i.e., are all of the sides of each triangle a complete segment from one point to another point?).

If so, i believe the answer is fairly straightforward....

56?
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 [#permalink] New post 03 Nov 2003, 05:33
8C3=56

Yes, but only if the points are the vertices of our triangles. Otherwise, the number of triangles is enormously more.
  [#permalink] 03 Nov 2003, 05:33
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Hard permutation/combination question

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