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# Hard permutation/combination question

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Joined: 02 Jan 2003
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Hard permutation/combination question [#permalink]  31 Oct 2003, 14:31
here is the question:
8 points lie on an xy plane. No more than 2 lie on the same line. How many triangles can you form with these points?

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leon
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you need to clarify this question. Are the triangles to be formed only with the given points as vertices? (i.e., are all of the sides of each triangle a complete segment from one point to another point?).

If so, i believe the answer is fairly straightforward....

56?
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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8C3=56

Yes, but only if the points are the vertices of our triangles. Otherwise, the number of triangles is enormously more.
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