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# How many points

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Senior Manager
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How many points [#permalink]  16 Jun 2005, 06:26
Can someone tell a short way of solving this ?
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ash
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CEO
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[#permalink]  16 Jun 2005, 06:40
equation of the line is y = 3/5 x + 30

for any x thats a multiple of 5, y is an integer.

Maximum x is 50. thus there are 11 x's for which y is an integer.

Thus there are 11 pairs.
Senior Manager
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[#permalink]  16 Jun 2005, 06:45
I was hoping for a shorter method......

BTW I used the same way as above to get the answer.
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[#permalink]  16 Jun 2005, 07:08
The equation is x/50 + y/30 = 1 or

y=(150-3x)/5

For y to be an integer with x also as an integer, x has to be zero or a multiple of 5.

y can be 30,27,24,..,0 or 11 values
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[#permalink]  16 Jun 2005, 07:40
I get 10...how do we get 11?
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Re: How many points [#permalink]  16 Jun 2005, 17:30
y = mx + c
m = -30/50 = -3/5
y = (-3/5) x + c
the integer co-ordinates of x that are divided by 5 are 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, and 50. so there are 11.
Re: How many points   [#permalink] 16 Jun 2005, 17:30
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# How many points

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