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# In a certain infinite sequence

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Senior Manager
Joined: 30 May 2005
Posts: 374
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Kudos [?]: 7 [0], given: 0

In a certain infinite sequence [#permalink]  02 Jul 2005, 21:56
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In a certain infinite sequence n(1)=7,n(2)=70,n(3)=700,n(x)=10*n(x-1)

Is the integer j a factor of every member of n?

S1. j is a prime number.

S2. j is a factor of more than one member of the sequence
Director
Joined: 18 Apr 2005
Posts: 549
Location: Canuckland
Followers: 1

Kudos [?]: 8 [0], given: 0

Re: DS - Infinite sequence divisior [#permalink]  02 Jul 2005, 23:31
AJB77 wrote:
In a certain infinite sequence n(1)=7,n(2)=70,n(3)=700,n(x)=10*n(x-1)

Is the integer j a factor of every member of n?

S1. j is a prime number.

S2. j is a factor of more than one member of the sequence

1) insuff - 7 yes, 5 and 2 no
2) 1 and 7 factors of every member, 2,5, 10, 70 etc are factors of more than one member but not all

1)+2) insuff, 7 yes and 5 and 2 no again

E.
Senior Manager
Joined: 17 Apr 2005
Posts: 377
Location: India
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Kudos [?]: 16 [0], given: 0

Re: DS - Infinite sequence divisior [#permalink]  03 Jul 2005, 00:13
AJB77 wrote:
In a certain infinite sequence n(1)=7,n(2)=70,n(3)=700,n(x)=10*n(x-1)

Is the integer j a factor of every member of n?

S1. j is a prime number.

S2. j is a factor of more than one member of the sequence

Shouldn't the general Xth term be n(x) = [10^(x-1)]*n.

Agree with sparky, E.

HMTG.
Current Student
Joined: 28 Dec 2004
Posts: 3392
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 13

Kudos [?]: 180 [0], given: 2

[#permalink]  03 Jul 2005, 09:18
i think the n(x)=n*(10^(x-1))

E it should be...

we have 3 primes, 7, 5 and 2

it could be anyone...
[#permalink] 03 Jul 2005, 09:18
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# In a certain infinite sequence

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