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Is 1/p>r/(r^2+2)?

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Senior Manager
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Is 1/p>r/(r^2+2)? [#permalink] New post 17 Jun 2008, 17:44
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

63% (02:02) correct 36% (00:49) wrong based on 46 sessions
Is 1/p>r/(r^2+2)?

(1) p=r
(2) r>0

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-1-p-r-r-2-2-1-p-r-2-r-86165.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Mar 2013, 04:47, edited 1 time in total.
Edited the question and added the OA.
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Re: DS: Inequalities [#permalink] New post 17 Jun 2008, 19:27
C

statement 1: + and negative numbers have different results

statement 2: nothing about p

together suff
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Re: DS: Inequalities [#permalink] New post 17 Jun 2008, 20:11
U r rite! C is the answer!

Detailed: 1/p > r/(r^2+2)

St1: p=r the inequality can be written as r^2 < r^2 + 2 when r>0 and as r^2 > r^2 + 2 for r<0

st2: r>0 is insufficient

Combining them: it is suffi.
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Re: Is 1/p>r/r^2+2? 1. p=r 2. r>0 [#permalink] New post 14 Mar 2013, 04:38
How do you solve this question?
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Re: Is 1/p>r/r^2+2? 1. p=r 2. r>0 [#permalink] New post 14 Mar 2013, 04:46
Expert's post
Re: Is 1/p>r/r^2+2? 1. p=r 2. r>0   [#permalink] 14 Mar 2013, 04:46
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