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Manager
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Which expression has the greatest value? (A) 1^{999}(B) 2^{300}(C) 3^{200}(D) 4^{100}(E) 16^{50}Source: GMAT Club Tests - hardest GMAT questions
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Intern
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A. 1^999 is what it is: 1.
B. 2^300
C. 3^200
D. 4^100: 4 can be written as 2^2. Therefore, the whole thing becomes (2^2)^100=2^200
E. 16^50: 16 can be written as 2^4. Accordingly, (2^4)^50=2^200.
It's either B or C. Logically guessing, if 2^3 is less than 3^2, then 2^300 must be less than 3^200. So I would go for C.
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CEO
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giantSwan wrote: ->How does this conversion work?
Which expression has the greatest value?
1^999 2^300 3^200 4^100 16^50 Yeah its C. 2^6 < 3^4 raise both side's power to 50 (2^6)^50 < (3^4)^502^300 < 3^200
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I think it can be done in this way -
1^999 = 1 2^300 = (2^3)^100 = 8^100 3^200 = (3^2)^100 = 9^100 4^100 = 4^100 16^50 = (4^2)^50 = 4^100
by the rule a^x > b^x if a>b we can say C i.e. 3^200 is the greatest
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Director
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C. I think you should take the nth root (say, ^100) of all numbers. 9>8>4=4>1
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Simplify?
1^999=1 2^300/100=2^3=8 3^200/100=3^2=9 4^100/100=4^1=4 16^50/100=16^.5=Fraction 1/16
Is my logic correct here? C looks good
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giantSwan wrote: Which expression has the greatest value? (A) 1^{999}(B) 2^{300}(C) 3^{200}(D) 4^{100}(E) 16^{50}Source: GMAT Club Tests - hardest GMAT questions A is always 1 D & E can be reduced to 2^200 so either B or C. B can be reduced to 2^300 = 4^150 = 8^100 C can be reduced to 3^300 = 9^150 hence C > B. SO answer is C
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I think you meant 3^{200} in C. Thus C is reduced to 9^{100}. The answer is still C, I just wanted to make things clearer. bangalorian2000 wrote: A is always 1 D & E can be reduced to 2^200 so either B or C. B can be reduced to 2^300 = 4^150 = 8^100 C can be reduced to 3^300 = 9^150 hence C > B. SO answer is C
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dzyubam wrote: I think you meant 3^{200} in C. Thus C is reduced to 9^{100}. The answer is still C, I just wanted to make things clearer. bangalorian2000 wrote: A is always 1 D & E can be reduced to 2^200 so either B or C. B can be reduced to 2^300 = 4^150 = 8^100 C can be reduced to 3^300 = 9^150 hence C > B. SO answer is C
Thanks for correcting the mistake.
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Its between B & C just take random case 2^3 and 3^2 and you get answer........c it is
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just expand all the values to be a power of 100 and u will know that C = 9 to the power of 100 and thats the largest
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A. 1.
B. 2^300 = 8^100
C. 3^200= 9^100
D. 4^100
E. 16^50 = 4^(2*50) = 4^100
Hence ans is C as 9^100 is the greatest
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Senior Manager
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giantSwan wrote: Which expression has the greatest value? (A) 1^{999}(B) 2^{300}(C) 3^{200}(D) 4^{100}(E) 16^{50}Source: GMAT Club Tests - hardest GMAT questions C is correct. Here is my 2 cents. 1^999 = 1 2^300 = (2^3)^100 = 8^100 3^200 = (3^2)^100 = 9^100 4^100 = (2^2)^100 = 2^200 < 2^300 16^50 = (2^4)^50 = 2^200 < 2^300 So, 3^200 = 9^100 is greatest.
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Which expression has the greatest value?
(A) 1 (B) 8^100 (C) 9^100 (D) 2^200 (E) 2^200
Hence C
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