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20 Sep 2008, 17:08
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A certain prime x is divided by 5 to get a fraction. Then its numerator is increased by 4 and its denominator doubled, after which the resulting fraction is reduced. The denominator of the result is odd. What is x?
1) 7
2) 5
3) 4
4) 3
5) 2
Answer: First, eliminate 4 as it is not a prime. Then either plug the choices in or notice that will have an odd denominator only if is even, which identifies as 2.
The correct answer is E.
My question: If the initial fraction is 2/5 aka 4/10 and the changed/ resulting fraction is 6/10 (2+4 and double denominator), how has the resulting fraction been reduced?
1) 7
2) 5
3) 4
4) 3
5) 2
Answer: First, eliminate 4 as it is not a prime. Then either plug the choices in or notice that will have an odd denominator only if is even, which identifies as 2.
The correct answer is E.
My question: If the initial fraction is 2/5 aka 4/10 and the changed/ resulting fraction is 6/10 (2+4 and double denominator), how has the resulting fraction been reduced?
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22 Sep 2008, 00:41
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Do you think our wording is wrong? If yes, could you please suggest any improvements?
The fraction \(\frac{6}{10}\) is reduced to \(\frac{3}{5}\):
\(\frac{6}{10}=\frac{\cancel{2}*3}{\cancel{2}*5}\).
The fraction \(\frac{6}{10}\) is reduced to \(\frac{3}{5}\):
\(\frac{6}{10}=\frac{\cancel{2}*3}{\cancel{2}*5}\).
22 Sep 2008, 15:31
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Thank you dzyubam for your response. I understand now what "reduced" means but I did assume it meant the resulting fraction was smaller. No I do not have any suggestions other than eliminating the "reduced" altogether and making the testers figure it out for themselves that the figure must be "reduced". Thank you.
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