I think it is B. from the information given, AC has to be hypoteneous. Then AB and AC become non-hypoteneous sides. so st taement 2 is suff.

Source?
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Guys , I think I cldnt explain my problem. Im not talking of OA. OA is B indeed 2 which i agree. My question is why is point D given in the question. there is no need for this. In case its a triangle, there have 2b only 3 points na? also BD height is confusing me.

This was a poorly written question. It could easily be argued that AB and BC are not "non-hypotenuse sides" because they are the hypotenuses of triangles ABD and BDC, respectively. BD is the only side in the entire problem that is not the hypotenuse of any triangle. Overall, very confusing. Could be improved with either an accompanying picture or with clarifying language in the problem. It was an easy problem - understanding the information they were giving you was ambiguous at best.

Distinct points A ,B, C,D form a right triangle ABC with a height BD . What is the value of AB times BC ?
1. AB=6
2. The product of the non-hypotenuse sides is equal to 24

I got so confused with why D is listed and if the order can be A,B, C or could be different. Is this intentional?

"If distinct points A, B, C, and D form a right triangle ABC with a height BD, what is the value of AB times BC?"

The language of this question appears at odds with the author's intent.

With respect to a triangle, the word "height" really only means "a line segment perpendicular to a triangle's edge, of a length equal to the distance of that edge from the opposite vertex." Height BD may or may not land D on the perimeter of the triangle. A line segment labeled "height" may just as easily be outside the triangle as inside the triangle, and is indeed outside the triangle in one example from a Grade 6 math text. "Height" means whatever helps you calculate the area of a triangle most easily; GMAC's OG12 does not use this term.

The term "altitude" would make the answer explanation work. From OG12 p.130: "The altitude of a triangle is the segment drawn from a vertex perpendicular to the side opposite that vertex." D must then lie on the perimeter of right triangle ABC, and B must be opposite the hypotenuse AC for D to be distinct from A and C.

Since GMAC does apparently regard "altitude" as fair game on the exam, and even gives the area of a triangle as "0.5*(base plus altitude)" on OG12 p.130, is there any chance of having this question amended to refer to "altitude BD" rather than "height BD" for future M04 takers?

Question here,

When they said that DB is the hight of ABC (right triangle) that means DB intersects with AC (hypotenuse), then is DB perpendicular on AC??

Yes,
If it says hight it is always perpendicular to the side which it crosses.
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Whats the OA?
Stmt 1: Quesrie: doesn't BD bisect AC? then,AD=AC....hmm?
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Could someone post a diagram? I think that would help me a lot. I don't understand where "D" is coming from either.

Since the stimulus states the triangle ABC is a right triangle, D must lie on one of the sides.


also,
One might assume the following,
If we draw the right triangle ABC with D lieing on AC.
S1 tells us that AB = 6. Since this is a right triangle, then the other sides are 8 and 10 by using the pythagorean triples 3-4-5. (use a factor of 2)

However,
the sides could also be 2.5, 6, 6.5 using the pyth. triple of 5-12-13 (use a factor of 1/2)

Therefore S1 is not sufficient.
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