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M04 #12

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Re: If distinct points A , B , C , and D form a right triangle [#permalink]

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01 Apr 2011, 23:01
Oh yes...Answer B is indeed correct.
I didn't understand the question correctly in the first place and thus chose C.

gmat1220 wrote:
Hello pesfunk
knowing the geometry of rt angled triang is different from knowing the area. The Ds question is more simply- do you know the area of the rt angled trig ABC?
S1 is insuff
S2 is suff. If you paraphrase it tells you the 1/2 of base *height is known. Hence area is known

Unless you confuse the question with what is the geometry of the triangle - you are good . C is overanalysis.

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Re: If distinct points A , B , C , and D form a right triangle [#permalink]

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02 Apr 2011, 05:58
Fluke - my friend,

Isnt the 2nd statement exactly what they are asking in the question?

am i missing something here?
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Re: If distinct points A , B , C , and D form a right triangle [#permalink]

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02 Apr 2011, 06:42
144144 wrote:
Fluke - my friend,

Isnt the 2nd statement exactly what they are asking in the question?

am i missing something here?

I believe you are correct!!!

Stem says:
ABC is a right angled triangle. My only concern here is that the question stem doesn't explicitly say that the triangle ABC is a right angled triangle, right angled at B. I am assuming that the triangle is right angled at B.

Now, Point D is located somewhere in the co-ordinate such that BD becomes the height.

Attached image is showing 3 of the possible scenarios where D can be located. D can superimpose A i.e. D and A can be the two points at the same co-ordinate, D and B can be the two points at the same co-ordinate or D can somewhere be on the line segment AC, which is the hypotenuse.

Now, we need to find out AB*BC. Note: we don't need to know AB and BC individually. So far we get "AB*BC", we are good.

St1: AB=6; We don't know anything about BC and thus AB*BC can't be found. Not Sufficient.
St2: The product of the non-hypotenuse sides is equal to 24. From the stem, we know AB and BC are the non-hypotenuse sides. Thus, the statement 2 is telling us exactly what we wanted to know. Sufficient.

Turns out that extra information about the BD was given just to provide some extraneous information and confuse the test takers. We could have done without that. Well!! I feel that there is some loop hole in this question and I don't consider it to be one of my favorites.
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ABC_RightAngleTriangle.PNG [ 7.17 KiB | Viewed 1773 times ]

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Re: If distinct points A , B , C , and D form a right triangle [#permalink]

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02 Apr 2011, 08:01
Im not sure its a real gmat question...
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02 May 2011, 09:14
If distinct points A ,B ,C and D form a right triangle ABC with a height BD , what is the value of AB times BC ?

1) AB = 6
2) The product of the non-hypotenuse sides is equal to 24.
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Re: M04: Question 12: Geometry [#permalink]

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02 May 2011, 13:22
Thanks for the question, but what are the answer choices?

(I think the answer is 52^1/2, but I have no way of knowing if I don't know the answer choices.)
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Re: M04: Question 12: Geometry [#permalink]

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02 May 2011, 16:58
The answer is B. If you draw a triangle as suggested, it's obvious that D lies on AC (hypotenuse)

(1)
AB is given, but we don't know BC (other non-hypotenuse side).
Not-sufficient.

(2)

Area of base * height = product of the non-hypotenuse sides = 24

Sufficient.
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23 Jul 2011, 19:16
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24 Jul 2011, 14:05
To create various possibilities, I had this diagram (as attached) in mind.
Somebody please point out my error.

Thanks.
Attachments

triangle ABC.docx [13.29 KiB]

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25 Jul 2011, 19:52
Guys can you pls draw dis .

I tried drawing nd got answer as C.
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product.doc [23.5 KiB]

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31 Aug 2011, 05:40
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ABC is a right triangle......the right angle can be any one out of A, B or C? Why does it have to be only B?
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31 Aug 2011, 08:13
teal wrote:
ABC is a right triangle......the right angle can be any one out of A, B or C? Why does it have to be only B?

Good catch; never thought that. The stem should have mentioned right-angled at B.

Anyone thinks otherwise? dzyubam?
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31 Aug 2011, 15:30
Thanks for getting back, fluke!
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05 Sep 2011, 13:49
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I just took this test.

I assumed that D should be a distinct pt. However, if the triangle is right-angled at A then the altitude BD can be drawn outside the triangular region ABC such that the BD will be parallel to AB or AC. In this case, the value of AB*BC will be 6*sqrt(52), which is different from the ans that we get if we assume that the triangle is right angled at B.

Please let me know if it I'm missing something.
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07 Nov 2011, 01:17
B
Statement 2 gives the product of AB and BC (which are non-hypotenuse sides). so sufficient
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26 Jul 2012, 06:22
Tvisha wrote:
Distinct points A, B, C, D form a right triangle ABC with a height BD. What is the value of AB times BC?

1. AB=6
2. The product of the non-hypotenuse sides is equal to 24

[Reveal] Spoiler: OA
B

could any one explain this?

given AB*BC = 2 *Area

1. AB is given, but we dont know anything abt area or BC..so cant answer the question hence options A and D are gone

2. so taking the right angled triangle, we know that the other product of non-hypotenuse sides is equal to twice the area and that is what the question is asking us. hence this gives the answer...so option B is the answer
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26 Jul 2012, 08:26
The answer cannot be B. Actually, the question is ambiguous. If we have triangle ABC as the right-angled triangle, it means that B = 90. Now we have two more triangles here, ADB and BDC and both these triangles are right-angled triangles (since D is the height of the triangle ABC and in Maths, height = perpendicular drawn from one vertex to the opposite side). If we say "non-hypotenuse sides", we have to be very clear as to which triangles non-hypotenuse sides we are referring to. As we can see from above, there would be 6 non-hypotenuse sides in this figure (because there are 3 right angled triangles). So the answer cannot be B.

Hope this helps!
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26 Jul 2012, 08:34
dreambeliever wrote:
I just took this test.

I assumed that D should be a distinct pt. However, if the triangle is right-angled at A then the altitude BD can be drawn outside the triangular region ABC such that the BD will be parallel to AB or AC. In this case, the value of AB*BC will be 6*sqrt(52), which is different from the ans that we get if we assume that the triangle is right angled at B.

Please let me know if it I'm missing something.

BD can never be parallel to AB since they intersect at the common point B. Also, BD (height) can never be parallel to AC as it has to be perpendicular to AC to qualify as height.

Hope this helps!
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26 Jul 2012, 09:06
Can anyone take a crack at drawing this diagram ?
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26 Jul 2012, 09:56
Bandesha1 wrote:
Can anyone take a crack at drawing this diagram ?

here it is.

Hope the diagram imparts more clarity to the ambiguity in the question.
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Geo_figure.JPG [ 19.1 KiB | Viewed 1191 times ]

Re: M04 #12   [#permalink] 26 Jul 2012, 09:56

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