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M04 #12

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Re: If distinct points A , B , C , and D form a right triangle [#permalink] New post 26 Jul 2012, 11:00
fluke wrote:
144144 wrote:
Fluke - my friend,

Isnt the 2nd statement exactly what they are asking in the question?

am i missing something here?


I believe you are correct!!!
2nd statement is telling us exactly what the question had asked.

Stem says:
ABC is a right angled triangle. My only concern here is that the question stem doesn't explicitly say that the triangle ABC is a right angled triangle, right angled at B. I am assuming that the triangle is right angled at B.

Now, Point D is located somewhere in the co-ordinate such that BD becomes the height.

Attached image is showing 3 of the possible scenarios where D can be located. D can superimpose A i.e. D and A can be the two points at the same co-ordinate, D and B can be the two points at the same co-ordinate or D can somewhere be on the line segment AC, which is the hypotenuse.

Now, we need to find out AB*BC. Note: we don't need to know AB and BC individually. So far we get "AB*BC", we are good.

St1: AB=6; We don't know anything about BC and thus AB*BC can't be found. Not Sufficient.
St2: The product of the non-hypotenuse sides is equal to 24. From the stem, we know AB and BC are the non-hypotenuse sides. Thus, the statement 2 is telling us exactly what we wanted to know. Sufficient.

Turns out that extra information about the BD was given just to provide some extraneous information and confuse the test takers. We could have done without that. Well!! I feel that there is some loop hole in this question and I don't consider it to be one of my favorites.


You are missing out on a very important word mentioned in the question - DISTINCT. The question states that A,B, C and D are distinct points. Hence the only valid figure here is the second one as D cannot superimpose any other point.

Am i missing something?
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Re: M04 #12 [#permalink] New post 26 Jul 2012, 12:24
Good one.

Did not find it tough though. One normally tends to imagine that the the right triangle has the non-hypotenuse sides parallel to either the X and Y axis. This problem becomes much easier when we imagine the right triangle with the hypotenuse parallel to the X-axis. That helps plot the point D easily.

B it is. :)
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Re: M04 #12 [#permalink] New post 26 Jul 2012, 12:45
avrgmat wrote:
Good one.

Did not find it tough though. One normally tends to imagine that the the right triangle has the non-hypotenuse sides parallel to either the X and Y axis. This problem becomes much easier when we imagine the right triangle with the hypotenuse parallel to the X-axis. That helps plot the point D easily.

B it is. :)

when you will be drawing a perpendicular from B to the side AC (i.e. drawing BD), two more right-angled triangles would be created, thus creating ambiguity. Check my previous posts for the ambiguity in the question I am referring to.
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Re: M04 #12 [#permalink] New post 26 Jul 2012, 13:01
BadgerNeeraj wrote:
The answer cannot be B. Actually, the question is ambiguous. If we have triangle ABC as the right-angled triangle, it means that B = 90. Now we have two more triangles here, ADB and BDC and both these triangles are right-angled triangles (since D is the height of the triangle ABC and in Maths, height = perpendicular drawn from one vertex to the opposite side). If we say "non-hypotenuse sides", we have to be very clear as to which triangles non-hypotenuse sides we are referring to. As we can see from above, there would be 6 non-hypotenuse sides in this figure (because there are 3 right angled triangles). So the answer cannot be B.

Hope this helps!


I figured the ambiguity as the height in Maths need not be parallel to any axis. As long as it is perpendicular to the sides, it can be considered at the height. In fact for that matter in a right-triangle (ABC), one on the non-hypotenuse sides can be considered the height. Why do we need a height BD then.

That said, the question does not state anywhere that the triangle ABC is the only right triangle formed between the points A,B,C and D. For that matter, the second statement just gives a rephrased version of the question asked.

B is the point of the right angle and hence AB times BC is effectively product of the non-hype sides of the triangle ABC.

But I get your point regarding the non-hypo sides. Overall this is a non-standard question which might not appear in the GMAT.
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Re: M04 #12 [#permalink] New post 26 Jul 2012, 22:24
Can any one help me so solve this question plz
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Re: M04 #12 [#permalink] New post 27 Jul 2012, 08:25
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BELOW IS REVISED VERSION OF THIS QUESTION WITH A SOLUTION:

A, B, C, and D are distinct points on a plane. If triangle ABC is a right angled and BD is a height of this triangle, what is the value of AB times BC ?

Since all points are distinct and BD is a height then B must be a right angle and AC must be a hypotenuse (so BD is a height from right angle B to the hypotenuse AC). Question thus asks about the product of non-hypotenuse sides AB and BC.

(1) AB = 6. Clearly insufficient.
(2) The product of the non-hypotenuse sides is equal to 24 --> directly gives us the value of AB*BC. Sufficient.

Answer: B.

Hope it's clear.
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Re: M04 #12 [#permalink] New post 30 Jul 2012, 22:30
Unless we know where D is, we cannot really determine the solution. BD was mentioned as 'a height'. But, not as 'the only height'.. So,answer should be 'E'
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Re: M04 #12 [#permalink] New post 31 Jul 2012, 00:52
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Re: m04, Q 12 [#permalink] New post 01 Aug 2012, 08:26
GMAT TIGER wrote:
ritula wrote:
Distinct points A,B , C , D form a right triangle ABC with a height BD . What is the value of AB times BC ?

1. AB = 6
2. The product of the non-hypotenuse sides is equal to 24

In this question, i fail to understand y is D given. Since all points are distinct then how cum BD is the height?


I think it is B. from the information given, AC has to be hypoteneous. Then AB and AC become non-hypoteneous sides. so st taement 2 is suff.

Source?

yes, i agree, point D is given only to confuse.the answer is B.
Re: m04, Q 12   [#permalink] 01 Aug 2012, 08:26
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