Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A 10 liter mixture of cranberry juice and water contains juice and water in the ratio of 3 : 2. 5 liters of the mixture are removed and replaced with pure juice and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of juice to water in the resulting mixture?

My solution: Original mixture has CJ:6 lts and water 4 lts. step 1: 5 lts are removed.Therefore, CJ remaining: 6 - {3/5 x 5} = 3lts. Water remaining: 4 - {2/5 x 5}=2lts. now 5 lts of CJ are added bringing the mixture to CJ:8 lts and water:2 lts.

step 2: 5 more lts are removed. amount of CJ removed: 8 x 3/5 = 4.8 lts amount of wtr removed:8 x 2/5= 0.2lts. 5 lts of CJ added Resulting in CJ: 8.20lts and 1.80 lts of water.

after 5 liter mixture is removed and 5 liter juice is added: J = 6 - 5(3/5) + 5 = 8 water = 4 - 5(3/5) = 2

after one more time 5 liter mixture is removed and 5 liter juice is added:

J = 8 - 5(4/5) + 5 = 9 water = 2 - 5(1/5) = 1

so J:W = 9:1. Thats E. Hope you got it.

suyashjhawar wrote:

A 10 liter mixture of cranberry juice and water contains juice and water in the ratio of 3 : 2. 5 liters of the mixture are removed and replaced with pure juice and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of juice to water in the resulting mixture?

1. 5 : 3 2. 6 : 4 3. 8 : 2 4. 17 : 3 5. 9 : 1

My solution: Original mixture has CJ:6 lts and water 4 lts. step 1: 5 lts are removed.Therefore, CJ remaining: 6 - {3/5 x 5} = 3lts. Water remaining: 4 - {2/5 x 5}=2lts. now 5 lts of CJ are added bringing the mixture to CJ:8 lts and water:2 lts.

step 2: 5 more lts are removed. amount of CJ removed: 8 x 3/5 = 4.8 lts amount of wtr removed:8 x 2/5= 0.2lts. 5 lts of CJ added Resulting in CJ: 8.20lts and 1.80 lts of water.

Your approach is somewhat correct. What you're messing up in the 2nd round is that you're keeping the ratio of Juice to Water at 3:2, as per the original ratio, instead of realizing that the ratio of Juice to Water is now different in the 2nd time. The ratio had changed after we removed 5 liters of the mixture and replaced it with Juice in the first round.

Hope that helps.

suyashjhawar wrote:

GMAT TIGER wrote:

J = (3/5)(10) = 6 W = 4

after 5 liter mixture is removed and 5 liter juice is added: J = 6 - 5(3/5) + 5 = 8 water = 4 - 5(3/5) = 2

after one more time 5 liter mixture is removed and 5 liter juice is added:

J = 8 - 5(4/5) + 5 = 9 water = 2 - 5(1/5) = 1

so J:W = 9:1. Thats E. Hope you got it.

suyashjhawar wrote:

A 10 liter mixture of cranberry juice and water contains juice and water in the ratio of 3 : 2. 5 liters of the mixture are removed and replaced with pure juice and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of juice to water in the resulting mixture?

1. 5 : 3 2. 6 : 4 3. 8 : 2 4. 17 : 3 5. 9 : 1

My solution: Original mixture has CJ:6 lts and water 4 lts. step 1: 5 lts are removed.Therefore, CJ remaining: 6 - {3/5 x 5} = 3lts. Water remaining: 4 - {2/5 x 5}=2lts. now 5 lts of CJ are added bringing the mixture to CJ:8 lts and water:2 lts.

step 2: 5 more lts are removed. amount of CJ removed: 8 x 3/5 = 4.8 lts amount of wtr removed:8 x 2/5= 0.2lts. 5 lts of CJ added Resulting in CJ: 8.20lts and 1.80 lts of water.

where did i mess up???

did'nt get the later part dude..missing something when the things getting replaced the second time.

yep.. this is much simpler question to answer as the ratios result in very nice integers....

first round: 5 litres removed => remaining is 3L juice + 2L water add 5L more juice => now 8L juice + 2L water => 8:2 second round: now remaining is 4L juice+ 1L water (5L is removed)... add 5L more juice => 9L juice+1L water =>final ratio 9:1

So without looking at the reveal I would say this. First of all we have ten liters in 3:2 ratio which is the same as 6L juice and 4 liters water. Then we take away 5L of fluid leaving 3L juice and 2L water and then add 5L juice. Now after one cycle we have 8 L juice and 2L water. We take away 5 L of fluid retaining 4L juice and 1L water. Then we add 5L juice. Now we have 9L juice and 1 L water. Ratio 9:1. ANSWER #5.

If this is helpful to you please give kudos. Thanks, Skip

ratio is 3:2 and mixture ir 10 lit. It can be expressed as 3x+2x=10 where x is a constant. 5x=10 => x=2. We have 6 lit juice and 4 lit water in 10 lit mixture.

Similarly for 5 lit, we have 3 lit juice and 2 lit water. Taking out this 5 lit means we are left with 6-3=3 lit juice and 4-2 = 4 lit water in the remaing 5 lit mixture.

Now we add 5 lit pure juice , which means the total mix is again 10 lit with the new composition as 3+5=8 lit juice and 2 lit water. Hence the new ratio is 8:2 or 4:1

Now if we take out 5 lit of mixture again. it means we are taking out 4 lit juice and 1 lit water. So the remaing is 4 lit juice and 1 lit water.

Again adding 5 lit of juice to it.. new comp is 4+5 =9 lit juice and 1 lit water.

10 lit Juice = 6lit Juice + 4 lit Water 5 lit taking out = 3lit + 2 lit water and 5 lit pure juice added = 8lit + 2lit water 5 lit taking out = 4lit + 1 lit water and 5 lit pure juice added = 9lit + 1lit water

Removing half of mixture and replacing it with pure juice simply removes half of water. Repeat it twice and you get 1/4 of initial amount or 1/10 of total.

1st - 60 % juice ; 40% water in 10 litres after 5 litres is removed; the composition still remains same 2nd - 5 litre pure juice (100%) is added in resultant mixture; juice= (60*5)/100 + 5 = 8 and water = 40 * 5/100 = 2 i.e. 80-20% in 10 litres again after 5 litres is removed; the composition still remains same 3rd - 5 litre pure juice (100%) is added in resultant mixture; juice = (80*5/100) + 5 = 9 and water =20*5/100 = 1 i.e. 9:1

No need of any explaination everyone knows how to solve it. Lets try a little different one. Give it a try posting.php?mode=post&f=140 _________________

If you liked my post, please consider a Kudos for me. Thanks!

so first for total 10 lts of mix contain juice and water in the ratio 3:2 the for total 5 lts 3 lts of juice is there then for total 10 lts of mixture contain 6 lts of juice and remaining 4 lts of water(we can also calculate as juice but waste of time)

The ratio of Juice to water is 6:4

if 5 liters of mixture is removed then we can calculate the removing ratio of juice to water as for 10 lts we have 6 lts of juice so for 5 lts we can have 3 lts (5 is half of the 10 so the ratio of juice and water must also be halved ) and remaining 2 lts water

now in present mixture we have 3 lts of juice and 2 lts of water then 5 liters of juice is added to the resultant mixture after removing 5 lts of juice and water so if we add 5 lts of juice the present 3 lts the latest ratio of juice to water is 8:2

then from latest mixture again 5 lts or mixture is removed ie for 10 lts of mixture we have 8 lts of juice so for 5 lts we can remove 4 lts of juice (just halved) and 1 lts of water then the ratio of juice to water before adding pure juice is 4:1 then if we add 5 lts of juice to existing 4 lts the the total resulting juice would be 9 and remaining l ltr is water so final ratio is 9:1 i.e E.

Given: Solution = 10 liters Juice: Water = 3:2 So, Juice = 6 liters and Water = 4 liters

First Draw: Take out 5 liters of solutions. The remaining solution contains: Juice = 3 liters and Water = 2 liters Add 5 liters of juice. Resulting solutions will contain: Juice = 8 liters and Water = 2 liters

Second Draw: Take out 5 liters of solutions. The remaining solution contains: Juice = 4 liters and Water = 1 liters Add 5 liters of juice. Resulting solutions will contain: Juice = 9 liters and Water = 1 liters

So, Juice:Water = 9:1

If you like this, do not forget to click on Kudos+1. Happy GMATing!! Cheers!!

A 10 liter mixture of cranberry juice and water contains juice and water in the ratio of 3 : 2. 5 liters of the mixture are removed and replaced with pure juice and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of juice to water in the resulting mixture?

10 = 6Juice + 4 Water

When 5 litre is removed ,because the ratio is 3:2 , 3L Juice and 2L Water is removed and when 5L juice is added then the above equation becomes

10=8Juice + 2 Water

In the second go , the ratio now is 4:1 , when we take out 5L of the mixture , 4L of Juice and 1L of Water is taken out and when we add 5L of pure juice the above equation becomes

Initial J: 10*3/5 W 10*2/5 round1: J: 10*3/5*1/2+5 W 10*2/5*1/2 10 in the numerator and 5*2 in denominator cancel out J: 8 W 2 round2: J: 8*1/2+5 = 9 W 2*1/2 =1

9:1

I know I could've calculated out the initial amounts, but I prefer to skip a step or two in the calculations when I can.

Juice to Water Ratio is 3:2 which is 6 L of Juice and 4 L of Water in the total quantity of 10 L. Step 1: Remove 5 L, which leaves 3 L of juice and 2 L of water. Step 2: Add 5 L of only Juice, which makes 8 L of juice and 2 L of water. Step 3: Remove 5 L, which leaves 4 L of juice and 1 L of water. Step 4: Add 5 L of only juice, which make 9 L of juice and 1 L of water.