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Re: M05 #36 - DS [#permalink]
tania wrote:
If a,b ,c and are positive distinct integers, is ( a/b)/c an integer?

1. c= 2
2. a= b+c




Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient

Above is the complete question


It's B because you can't pick a set of integers that are distinct and will result in an integer.

The answer to the questions is no, you can't get an integer..

Try any set of integers

a = b + c
b = 2 c = 4 a = 6
6/2 / 4 = 3/4 not an integer..

Just pick random numbers and you will never get an integer
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Re: M05 #36 - DS [#permalink]
thnx a for such a quick response...is there any other generic way of solving such questions?
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Re: M05 #36 - DS [#permalink]
[quote="tania"]If a,b ,c and are positive distinct integers, is ( a/b)/c an integer?

1. c= 2
2. a= b+c


The way I did it:
1. doesnt give us any real info
NS
2. a=b+c
divide both sides by b+c
a/(b+c)= 1
a/b + a/c = 1
IF they are distinct positive integers, this will never give an answer that works. will be fractions unless they are the same number, which the stem stipulates they can not be.

B is suff
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Re: M05 #36 - DS [#permalink]
That was a clear cut explanation. Thnx a lot .

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