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# m12#9

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Manager
Joined: 13 Dec 2009
Posts: 79
Followers: 1

Kudos [?]: 37 [0], given: 20

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22 Feb 2010, 00:01
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What is the remainder of $$\frac{(p^2)}{12}$$ ?

1. p is odd
2. p is prime
(C) 2008 GMAT Club - m12#9

OE: Statements (1) and (2) combined are insufficient. For $$p=3$$ the answer would be 9, for any prime $$p$$ bigger than 3, the answer would be 1.

I agree with the OA, but is it true that $$\frac{(3^2)}{12}$$ has a remainder 9!? I thought that the remainder is 0.
Can anybody clarify this issue?
CIO
Joined: 02 Oct 2007
Posts: 1218
Followers: 94

Kudos [?]: 911 [1] , given: 334

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22 Feb 2010, 03:28
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Here's a quote from wikipedia:
Quote:
In arithmetic, when the result of the division of two integers cannot be expressed with an integer quotient, the remainder is the amount "left over."

http://en.wikipedia.org/wiki/Remainder

In your example, 9 is a remainder because 9 is less than 12 and there is no integer quotient.
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Manager
Joined: 13 Dec 2009
Posts: 79
Followers: 1

Kudos [?]: 37 [0], given: 20

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22 Feb 2010, 03:53
Thank you dzyubam for your help!

Quote:
When dividing 3 by 10, 3 is the remainder as we always take the front number as the remainder when the second number is of higher value.
sourse: http://en.wikipedia.org/wiki/Remainder
Re: m12#9   [#permalink] 22 Feb 2010, 03:53
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# m12#9

Moderator: Bunuel

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