M15 #35 : Retired Discussions [Locked]
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# M15 #35

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Status: mission completed!
Joined: 02 Jul 2009
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Kudos [?]: 853 [2] , given: 621

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06 Nov 2010, 01:13
2
KUDOS
Hi guys:
It seems that explanation of both 1) and 2) are not so good.

in equation x^2Y^3=200 we can find that $$(5^2)*(2^3)=200$$ - here is the point that x may be 5 or -5. Unless we can decide it, we can not solve the DS problem.
Y is positive since 200 is positive.

1) we are given that y is an integer- tells us nothing,
x*y=-10 or X*y=10 - not sufficient

2) $$x/y=2.5$$ - tells that either both x and y are positive or negative. We know that y is positive so x - must be positive, thus we can find the value of x*y.
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08 Nov 2010, 01:04
Thank you! +1. I'll look into it.
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Re: M15 #35   [#permalink] 08 Nov 2010, 01:04
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# M15 #35

Moderator: Bunuel

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