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M16#11

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Re: M16#11 [#permalink] New post 23 Jun 2011, 16:19
May be its a stupid question - but why are we not considering negative integers here? The questions says three digit integers!
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Re: M16#11 [#permalink] New post 26 Jun 2012, 06:49
A good question that illustrates the need to know certain simple but important formulae when it comes to topics such as Counting and Probability.

I solved using Bunuel's mathematical approach as well. Nothing more to add.

Cheers,
Der alte Fritz


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Re: M16#11 [#permalink] New post 26 Jun 2012, 10:31
Nos. divided by 3 between 100 and 999 (including); starting 102,105....till 999 are {(999-102=897/3)+1 }=300
Therefore, nos. not divided by 300 between 100 & 999 = {(total nos between 100&999 ) minus nos. divided by 3}= [ {(999-100)+1}-300]=600

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Re: M16#11   [#permalink] 26 Jun 2012, 10:31
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