In a certain company, employees receive their salary on a monthly basis and are paid on either 10th or 20th of each month. If 65 percent of all managers are paid on 10th of each month and 79% of employees who are paid on 20th of each month are not managers, what percent of the company employees are managers?
the answer cannot be derived from the data provided
Here's what I did:
on the 20th, 0.35M = .21 E (because 35% of managers will get paid on the 20th; 21% of employees are managers)
therefore, M/E = 60%
21% of those paid on the 20th are managers, it doesn't mean that 21% of all employees are managers.
There are employees paid on the 10th, those paid on the 20th are not all the non-manager employees.
Also, managers can be divided into two groups: those paid on the 10th, and those paid on the 20th.
And you don't know anything about the employees (non-managers) paid on the 10th.
Try to use the 2 X 2 table method and you will see that you cannot fill it out. Or the Venn diagram.
PhD in Applied Mathematics
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