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M21#32

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Manager
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M21#32 [#permalink] New post 12 Oct 2009, 17:11
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This question should be edited. Adding a comma would do.

If 5 dollars and 35 crowns are equivalent to 7 pounds and 4 dollars and 4 pounds are equivalent to 56 crowns, what is the dollar equivalent of 1 pound and 28 crowns?

(C) 2008 GMAT Club - m21#32

* $7.00
* $7.50
* $8.50
* $9.00
* $10.00

Write 5d + 35c = 7p and 4d + 4p = 56c . Solving this system for p , we get p = \frac{5}{3}d . Solving this system for c , we get c = \frac{4}{21}d . 1 pound and 28 crowns = \frac{5}{3}d + 28*\frac{4}{21}d = 7d .
The correct answer is A.

The question should be rewritten as the text is ambiguous. It could either mean that:
1) 35 crowns are equivalent to 7 pounds; 4 dollars and 4 pounds are equivalent to 56, or
2) 5 dollars and 35 crowns are equivalent to 7 pounds and 4 dollars; 4 pounds are equivalent to 56 crowns

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Re: M21#32 [#permalink] New post 13 Oct 2009, 13:11
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I agree that the question is definitely ambiguous. I suggest that it be rewritten to say:

If 5 dollars and 35 crowns is equivalent to 7 pounds, and 4 dollars and 4 pounds is equivalent to 56 crowns, 1 pound and 28 crowns is equivalent to how many dollars?

powerka wrote:
This question should be edited. Adding a comma would do.

If 5 dollars and 35 crowns are equivalent to 7 pounds and 4 dollars and 4 pounds are equivalent to 56 crowns, what is the dollar equivalent of 1 pound and 28 crowns?

(C) 2008 GMAT Club - m21#32

* $7.00
* $7.50
* $8.50
* $9.00
* $10.00

Write 5d + 35c = 7p and 4d + 4p = 56c . Solving this system for p , we get p = \frac{5}{3}d . Solving this system for c , we get c = \frac{4}{21}d . 1 pound and 28 crowns = \frac{5}{3}d + 28*\frac{4}{21}d = 7d .
The correct answer is A.

The question should be rewritten as the text is ambiguous. It could either mean that:
1) 35 crowns are equivalent to 7 pounds; 4 dollars and 4 pounds are equivalent to 56, or
2) 5 dollars and 35 crowns are equivalent to 7 pounds and 4 dollars; 4 pounds are equivalent to 56 crowns

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**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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Re: M21#32 [#permalink] New post 13 Oct 2009, 22:45
Thank you guys! +1 to both. I've edit the question per Allen's suggestion.
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Re: M21#32   [#permalink] 13 Oct 2009, 22:45
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