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Median

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Senior Manager
Joined: 08 Nov 2008
Posts: 308
Followers: 2

Kudos [?]: 36 [0], given: 7

Median [#permalink]  29 Mar 2009, 09:05
00:00

Difficulty:

(N/A)

Question Stats:

70% (01:25) correct 30% (00:57) wrong based on 8 sessions
Attachment:

Median.jpg [ 46.89 KiB | Viewed 2003 times ]

pls discuss !!
Attachments

median.doc [62 KiB]

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"CEO in making"

Manager
Joined: 07 Feb 2009
Posts: 50
Followers: 0

Kudos [?]: 12 [0], given: 1

Re: Median [#permalink]  03 Apr 2009, 00:53
Weighted median needs to be calculated, can anyone plz explain the solution.
I think it is based on standard deviation basics.
Intern
Joined: 03 Apr 2009
Posts: 11
Followers: 0

Kudos [?]: 8 [0], given: 0

Re: Median [#permalink]  03 Apr 2009, 01:31
E. 6

Since I so recently taught middle school, I took a basic approach. I listed 1 nine times, 2 four times, 3 one time, 4 two times, 5 one time, 6 eight times, and 7 ten times. You can then see that 6 is the middle number.

However, you didn't even have to list them all. You can see that the 18th number will be the middle number, so you could stop with the first 6.
Intern
Joined: 03 Apr 2009
Posts: 2
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Kudos [?]: 0 [0], given: 0

Re: Median [#permalink]  03 Apr 2009, 01:49
tenaman10 wrote:
pls discuss !!

E - 6... for the first... for reasons explained above
B - 1/6... for the second

assume mean of 20 nos as x. So n=4x.
sum of 21 nos is 20x + 4x = 24x

n/24x = 20x/24x = 1/6
Intern
Joined: 29 Dec 2006
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Re: Median [#permalink]  17 Apr 2009, 19:22
thegr81 wrote:
tenaman10 wrote:
pls discuss !!

E - 6... for the first... for reasons explained above
B - 1/6... for the second

assume mean of 20 nos as x. So n=4x.
sum of 21 nos is 20x + 4x = 24x

n/24x = 20x/24x = 1/6

i agree with b for the second question.
i solved by picking numbers. to make it easy i used 1-20 for the first 20 numbers. given that, n came out to be 42. then i took n/sum of all the numbers, including n (sum of consecutive numbers is avg (middle number) * # of terms).
Re: Median   [#permalink] 17 Apr 2009, 19:22
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