Find all School-related info fast with the new School-Specific MBA Forum

It is currently 25 Jul 2016, 22:00
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Multiples...

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Manager
Manager
avatar
Joined: 01 Jun 2006
Posts: 77
Followers: 1

Kudos [?]: 1 [0], given: 0

Multiples... [#permalink]

Show Tags

New post 17 Dec 2006, 06:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Q)
Attachments

gclubb2.JPG
gclubb2.JPG [ 19.36 KiB | Viewed 553 times ]

Manager
Manager
avatar
Joined: 15 Nov 2006
Posts: 219
Location: Ohio
Followers: 1

Kudos [?]: 43 [0], given: 0

 [#permalink]

Show Tags

New post 17 Dec 2006, 08:36
If 450Y=X3
That means Y must be a factor of 450
Factors of 450=2X5X5X3X3
Thereofore, answer is (D). III only
Manager
Manager
avatar
Joined: 01 Jun 2006
Posts: 77
Followers: 1

Kudos [?]: 1 [0], given: 0

 [#permalink]

Show Tags

New post 17 Dec 2006, 09:14
The ans is B.....anyone...can shed light on this...
Senior Manager
Senior Manager
avatar
Joined: 08 Jun 2006
Posts: 340
Location: Washington DC
Followers: 1

Kudos [?]: 38 [0], given: 0

 [#permalink]

Show Tags

New post 17 Dec 2006, 09:21
450Y=X3
=>5^2 * 3^2 * 2 *Y = n^3
to make y a perfect cube, it has to be multiple of 5 * 3 * 2^2

so that n^3 = (5^2 * 3^2 * 2) * ( 5 * 3 * 2^2) K = (5 * 3 * 2)^3 * k
here k is another + ve integer

so Only B stands..
Manager
Manager
avatar
Joined: 01 Jun 2006
Posts: 77
Followers: 1

Kudos [?]: 1 [0], given: 0

 [#permalink]

Show Tags

New post 17 Dec 2006, 09:27
great stuff...anindyat....
  [#permalink] 17 Dec 2006, 09:27
Display posts from previous: Sort by

Multiples...

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.