Multiples... : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 22 Jan 2017, 09:49

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Multiples...

Author Message
Manager
Joined: 01 Jun 2006
Posts: 77
Followers: 1

Kudos [?]: 1 [0], given: 0

### Show Tags

17 Dec 2006, 05:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Q)
Attachments

gclubb2.JPG [ 19.36 KiB | Viewed 607 times ]

Manager
Joined: 15 Nov 2006
Posts: 219
Location: Ohio
Followers: 1

Kudos [?]: 55 [0], given: 0

### Show Tags

17 Dec 2006, 07:36
If 450Y=X3
That means Y must be a factor of 450
Factors of 450=2X5X5X3X3
Thereofore, answer is (D). III only
Manager
Joined: 01 Jun 2006
Posts: 77
Followers: 1

Kudos [?]: 1 [0], given: 0

### Show Tags

17 Dec 2006, 08:14
The ans is B.....anyone...can shed light on this...
Senior Manager
Joined: 08 Jun 2006
Posts: 340
Location: Washington DC
Followers: 1

Kudos [?]: 48 [0], given: 0

### Show Tags

17 Dec 2006, 08:21
450Y=X3
=>5^2 * 3^2 * 2 *Y = n^3
to make y a perfect cube, it has to be multiple of 5 * 3 * 2^2

so that n^3 = (5^2 * 3^2 * 2) * ( 5 * 3 * 2^2) K = (5 * 3 * 2)^3 * k
here k is another + ve integer

so Only B stands..
Manager
Joined: 01 Jun 2006
Posts: 77
Followers: 1

Kudos [?]: 1 [0], given: 0

### Show Tags

17 Dec 2006, 08:27
great stuff...anindyat....
17 Dec 2006, 08:27
Display posts from previous: Sort by