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Number Properties Problem Solving-HELP

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Intern
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Number Properties Problem Solving-HELP [#permalink] New post 04 Feb 2005, 12:36
How would you solve this?

If p & q are positive integers, how many integers are larger than pq and smaller than p(q+2)?

a) 3
b) p+2
c) p-2
d) 2p-1
e) 2p+1

I understand that picking numbers is one way to go. But, what is confusing me is the second part of the sentence. "How many integers are...." What does this exactly mean?
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 [#permalink] New post 04 Feb 2005, 13:37
numbers lie between pq and pq+2p

numbers could be pq+1,pq+2,.......pq+2p-1

no. of numbers= 2p-1

D is the answer.
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 [#permalink] New post 05 Feb 2005, 06:39
i wud pick numbers and move on got D
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 [#permalink] New post 06 Feb 2005, 01:03
Same as everbody here. I think D is the OA.

to give you the details :

exemple 1 : p=3 and q=5
pq = 15
p(q+2)=21
numbers larger than 15 but less than 21 (be careful , not equal...) : 5

exemple 2 : p=4 and q=8
pq = 32
p(q+2)=40
numbers larger than 32 but less than 40 (be careful , not equal...) : 7

Now you check with the answers and find the one that matches with your answers...it will be D
  [#permalink] 06 Feb 2005, 01:03
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