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# Number Properties Problem Solving-HELP

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Intern
Joined: 31 Jan 2005
Posts: 9
Followers: 0

Kudos [?]: 0 [0], given: 0

Number Properties Problem Solving-HELP [#permalink]  04 Feb 2005, 12:36
How would you solve this?

If p & q are positive integers, how many integers are larger than pq and smaller than p(q+2)?

a) 3
b) p+2
c) p-2
d) 2p-1
e) 2p+1

I understand that picking numbers is one way to go. But, what is confusing me is the second part of the sentence. "How many integers are...." What does this exactly mean?
Intern
Joined: 15 Dec 2004
Posts: 36
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numbers lie between pq and pq+2p

numbers could be pq+1,pq+2,.......pq+2p-1

no. of numbers= 2p-1

Director
Joined: 07 Jun 2004
Posts: 614
Location: PA
Followers: 3

Kudos [?]: 289 [0], given: 22

i wud pick numbers and move on got D
VP
Joined: 13 Jun 2004
Posts: 1122
Location: London, UK
Schools: Tuck'08
Followers: 7

Kudos [?]: 31 [0], given: 0

Same as everbody here. I think D is the OA.

to give you the details :

exemple 1 : p=3 and q=5
pq = 15
p(q+2)=21
numbers larger than 15 but less than 21 (be careful , not equal...) : 5

exemple 2 : p=4 and q=8
pq = 32
p(q+2)=40
numbers larger than 32 but less than 40 (be careful , not equal...) : 7

Now you check with the answers and find the one that matches with your answers...it will be D
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