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Number Properties Problem Solving-HELP

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Intern
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Number Properties Problem Solving-HELP [#permalink] New post 04 Feb 2005, 12:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How would you solve this?

If p & q are positive integers, how many integers are larger than pq and smaller than p(q+2)?

a) 3
b) p+2
c) p-2
d) 2p-1
e) 2p+1

I understand that picking numbers is one way to go. But, what is confusing me is the second part of the sentence. "How many integers are...." What does this exactly mean?
Intern
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 [#permalink] New post 04 Feb 2005, 13:37
numbers lie between pq and pq+2p

numbers could be pq+1,pq+2,.......pq+2p-1

no. of numbers= 2p-1

D is the answer.
Director
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 [#permalink] New post 05 Feb 2005, 06:39
i wud pick numbers and move on got D
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 [#permalink] New post 06 Feb 2005, 01:03
Same as everbody here. I think D is the OA.

to give you the details :

exemple 1 : p=3 and q=5
pq = 15
p(q+2)=21
numbers larger than 15 but less than 21 (be careful , not equal...) : 5

exemple 2 : p=4 and q=8
pq = 32
p(q+2)=40
numbers larger than 32 but less than 40 (be careful , not equal...) : 7

Now you check with the answers and find the one that matches with your answers...it will be D
  [#permalink] 06 Feb 2005, 01:03
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Number Properties Problem Solving-HELP

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