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# Number property

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Manager
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Number property [#permalink]  25 Mar 2009, 22:11
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Is y – x positive?
(1) y > 0
(2) x = 1 - y
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Manager
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Re: Number property [#permalink]  26 Mar 2009, 04:32
My ans is also E.

Stat 1 doesn't give any info about y – x as it doesn't talk about x.

Stat 2 says --> x = 1 - y, lets use it find out the sign of y-x:
y-x = y-(1-y) = 2y-1
y-x can be positive only if 2y-1>0 or, y>1/2

Even if we combine both statements, we can't say that y>1/2, even if we say y>0(from stat 1).
Manager
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Re: Number property [#permalink]  27 Mar 2009, 15:25
ImO: b

X=1-y; x-y=1 +ive. so, x>y; y>x?..No.
Senior Manager
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Re: Number property [#permalink]  27 Mar 2009, 18:29
milind1979 wrote:
Is y – x positive?
(1) y > 0
(2) x = 1 - y
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

I think it's E.

In statement 1 x can be positive, or negative, nothin else is known - insuff.
In statement 2 both x and y can be either positive, or negative - insuff.

Combining both statements does not help - x can be either negative or positive, and it cannot be determined whether x < or >y in case x is positive.
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Re: Number property [#permalink]  14 Oct 2009, 08:13
E
If x and y is positive integer we can have C as the ans
Senior Manager
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Re: Number property [#permalink]  14 Oct 2009, 08:39
IMO C.

Is y – x positive?
(1) y > 0
(2) x = 1 - y

statement 1) NOT Sufficient , when x>y its negative and when y>x its positive

statement 2) NOT sufficient, given that x+y =1, we can say if y>0 then x<=0 (eg y=1 then x=0 and y-x is positive but when y=2 and x=-1 , y-x is positive)
when x>0 then y<=0 (eg x=1 then y=0 and y-x is negative or when x=2 then y=-1 ,y-x is negative)

combining stmt 1 and 2: from stmt 1 we know y>0 and from stmt we know that y-x is always positive when y>0 (highlighted in red above)

I see the original post from Mar 2009, can we get an OA for this ?
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Last edited by srini123 on 14 Oct 2009, 08:42, edited 1 time in total.
Manager
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Re: Number property [#permalink]  14 Oct 2009, 08:41
pmal04 wrote:
ImO: b

X=1-y; x-y=1 +ive. so, x>y; y>x?..No.

Rewording the equation would give x+y=1
Manager
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Re: Number property [#permalink]  14 Oct 2009, 08:47
IMO C

1 - Insufficient
2 - Insufficient

But together Y > 0

Therefore X =< 0

Original equation would be +Y - (-X) = Y + X
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Re: Number property [#permalink]  14 Oct 2009, 09:30
Expert's post
hogann wrote:
IMO C

1 - Insufficient
2 - Insufficient

But together Y > 0

Therefore X =< 0

Original equation would be +Y - (-X) = Y + X

Red part is not correct.

Q: is y>x

(1) Y>0 insufficient
(2) x+y=1 insufficient

(1)+(2) x=-10 y=11 (y>0 x+y=1) --> y>x BUT x=0.9 y=0.1 (y>0 x+y=1) --> y<x not sufficient

E.
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Manager
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Re: Number property [#permalink]  14 Oct 2009, 09:43
Bunuel wrote:

Q: is y>x

(1) Y>0 insufficient
(2) x+y=1 insufficient

(1)+(2) x=-10 y=11 (y>0 x+y=1) --> y>x BUT x=0.9 y=0.1 (y>0 x+y=1) --> y<x not sufficient

E.

I wish GMAT questions only dealt with Integers, life would be much easier.
Senior Manager
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Re: Number property [#permalink]  14 Oct 2009, 09:50
Bunuel wrote:
hogann wrote:
IMO C

1 - Insufficient
2 - Insufficient

But together Y > 0

Therefore X =< 0

Original equation would be +Y - (-X) = Y + X

Red part is not correct.

Q: is y>x

(1) Y>0 insufficient
(2) x+y=1 insufficient

(1)+(2) x=-10 y=11 (y>0 x+y=1) --> y>x BUT x=0.9 y=0.1 (y>0 x+y=1) --> y<x not sufficient

E.

Thanks for poiting this out.

Wow - I missed checking for fractions as x,y - damn!!!
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Re: Number property   [#permalink] 14 Oct 2009, 09:50
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