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# odd number/kaplan

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odd number/kaplan [#permalink]  12 Nov 2009, 15:32
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83% (01:42) correct 16% (00:45) wrong based on 0 sessions
Dear All,
Here is the question :
"If both the product and sum of four integers are even, which of the following could be the number of even integers in the group ?"
Among the answers is "0", but it's a bad answer. I don't understand why and the explanation from the Kaplan is quite confusing for me.
Please S.M.S (Save My Soul) !
Thanks !
Marc

If both the products and sum of four integers are even, which of the following could
be the number of even integers in the group?
I. 0
II. 2
III. 4

a) I only
b) II only
c) III only
d) II and III
e) I, II, III
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Re: odd number/kaplan [#permalink]  12 Nov 2009, 15:42
marcos4 wrote:
Dear All,
Here is the question :
"If both the product and sum of four integers are even, which of the following could be the number of even integers in the group ?"
Among the answers is "0", but it's a bad answer. I don't understand why and the explanation from the Kaplan is quite confusing for me.
Please S.M.S (Save My Soul) !
Thanks !
Marc

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Joined: 02 Sep 2009
Posts: 11628
Followers: 1802

Kudos [?]: 9611 [1] , given: 829

Re: odd number/kaplan [#permalink]  12 Nov 2009, 15:55
1
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Welcome to the forum Marcos4.

Edited your post. Added the original question as I had it in my database. Also moved the topic to the Problem Solving forum from DS forum.

As for the question:

If both the products and sum of four integers are even, which of the following could
be the number of even integers in the group?

I. 0
II. 2
III. 4

a) I only
b) II only
c) III only
d) II and III
e) I, II, III
a+b+c+d=even and a*b*c*d=even.

For the sum of 4 integers to be even, group should contain 0, 2 or 4 even numbers. So possible scenarios are 0, 2, or 4 even numbers among 4.

For the product of the integers to be even at least one of them should be even. So 1, 2, 3, or all 4 numbers from a,b,c,d should be even. If there is 0 even number among them, it means that all 4 integers are odd, the product of four odd integers is odd. Hence there can not be 0 even number. So possible scenarios are 1, 2, 3 or 4 even numbers among 4.

Both conditions to be met: there can be 2 or 4 even numbers among 4.

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Re: odd number/kaplan [#permalink]  12 Nov 2009, 16:15
Bunuel wrote:
Welcome to the forum Marcos4.

Edited your post. Added the original question as I had it in my database. Also moved the topic to the Problem Solving forum from DS forum.

As for the question:

a+b+c+d=even and a*b*c*d=even.

For the sum of 4 integers to be even, group should contain 0, 2 or 4 even numbers. So possible scenarios are 0, 2, or 4 even numbers among 4.

For the product of the integers to be even at least one of them should be even. So 1, 2, 3, or all 4 numbers from a,b,c,d should be even. If there is 0 even number among them, it means that all 4 integers are odd, the product of four odd integers is odd. Hence there can not be 0 even number. So possible scenarios are 1, 2, 3 or 4 even numbers among 4.

Both conditions to be met: there can be 2 or 4 even numbers among 4.

thanks bunuel...yes, definitely d
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Re: odd number/kaplan [#permalink]  12 Nov 2009, 18:28
lagomez wrote:
marcos4 wrote:
Dear All,
Here is the question :
"If both the product and sum of four integers are even, which of the following could be the number of even integers in the group ?"
Among the answers is "0", but it's a bad answer. I don't understand why and the explanation from the Kaplan is quite confusing for me.
Please S.M.S (Save My Soul) !
Thanks !
Marc

I think I should have asked first, actually I don't know how editors like Kaplan react if you write the full question with the full answers from their book.

So I tried to copy only part of it as a "sample" but it wasn't enough to be understood.

Sorry !
Marc
Re: odd number/kaplan   [#permalink] 12 Nov 2009, 18:28
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