Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

100% (01:44) correct
0% (00:00) wrong based on 3 sessions

HideShow timer Statistics

There are 70 students in Math or English or German. Exactly 40 are in Math, 30 in German, 35 in English and 15 in all three courses. How many students are enrolled in exactly two of the courses? Math, English and German.

I think the OA makes perfect sense. And you cannot just ignore the term exactly. Exactly two means that they are not enrolled in all three classes. The simplest way to extract info from what's given is to draw a Venn Diagram.

Attachment:

File comment: Venn Diagram

c73058.jpg [ 19.92 KiB | Viewed 1633 times ]

So, from this picture, we are asked to find out what \(x+y+z\) is.

Let's look at given information and form the constraints:

Total = 70

\(x+y+z+a+b+c+15 = 70\)

\((x+y+z) + (a+b+c) = 55\)

Total Math = 40

\(x+y+a+15 = 40\)

\(x+y = 25-a\)

Total German = 30

\(y+z+c+15 = 30\) \(y+z = 15 -c\)

Total English = 35

\(x+z+b+15 = 35\)

\(x+z = 20-b\)

So now combining all the bolded equations regarding totals of each subject we get

\(2(x+y+z) = 15+25+20 - (a+b+c) = 60 - (a+b+c)\)

So \((a+b+c) = 60 - 2(x+y+z)\)

Now substituting this into the first equation regarding total students, we get

\((x+y+z) + 60 - 2(x+y+z) = 55\)

Hence \(x+y+z = 5\)

nravi4: The mistake you made in getting 50 is this. You counted the students enrolled in two of three subjects, but not strictly so. So your calculation includes the central space of 15 which is students enrolled in all three subjects for each subject you counted. So to get to the answer from your answer you need to do \(50 - (3*15) = 5\)

I think the OA makes perfect sense. And you cannot just ignore the term exactly. Exactly two means that they are not enrolled in all three classes. The simplest way to extract info from what's given is to draw a Venn Diagram.

Attachment:

c73058.jpg

So, from this picture, we are asked to find out what \(x+y+z\) is.

Let's look at given information and form the constraints:

Total = 70

\(x+y+z+a+b+c+15 = 70\)

\((x+y+z) + (a+b+c) = 55\)

Total Math = 40

\(x+y+a+15 = 40\)

\(x+y = 25-a\)

Total German = 30

\(y+z+c+15 = 30\) \(y+z = 15 -c\)

Total English = 35

\(x+z+b+15 = 35\)

\(x+z = 20-b\)

So now combining all the bolded equations regarding totals of each subject we get

\(2(x+y+z) = 15+25+20 - (a+b+c) = 60 - (a+b+c)\)

So \((a+b+c) = 60 - 2(x+y+z)\)

Now substituting this into the first equation regarding total students, we get

\((x+y+z) + 60 - 2(x+y+z) = 55\)

Hence \(x+y+z = 5\)

nravi4: The mistake you made in getting 50 is this. You counted the students enrolled in two of three subjects, but not strictly so. So your calculation includes the central space of 15 which is students enrolled in all three subjects for each subject you counted. So to get to the answer from your answer you need to do \(50 - (3*15) = 5\)

Hope this is clear.

Hi

cant we take 'a' as 40 here as it is mentioned exactly 40 on math?

It says that exactly 40 are in math, not that 40 are in ONLY math. The people who take Math and English or Math and German or even all three are also in math, aren't they not? So you can't take a to be 40 since 40 is the sum of a,x, y and 15, i.e. people who take only Math, people who take Math and English, people who take Math and German and people who take all three. Hope this is clear.

It says that exactly 40 are in math, not that 40 are in ONLY math. The people who take Math and English or Math and German or even all three are also in math, aren't they not? So you can't take a to be 40 since 40 is the sum of a,x, y and 15, i.e. people who take only Math, people who take Math and English, people who take Math and German and people who take all three. Hope this is clear.

Since my last post, I’ve got the interview decisions for the other two business schools I applied to: Denied by Wharton and Invited to Interview with Stanford. It all...

[rss2posts title=The MBA Manual title_url=https://mbamanual.com/2016/11/22/mba-vs-mim-guest-post/ sub_title=MBA vs. MiM :3qa61fk6]Hey, guys! We have a great guest post by Abhyank Srinet of MiM-Essay . In a quick post and an...

Marketing is one of those functions, that if done successfully, requires a little bit of everything. In other words, it is highly cross-functional and requires a lot of different...