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When tossed, a certain coin has the probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land on the same side each time?

A. 1/8
B. 1/4
C. 1/3
D. 3/8
E. 1/2

I chose A (1/2)(1/2)(1/2) = 1/8 (independent events) is this wrong?

When tossed, a certain coin has the probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land on the same side each time?

A. 1/8 B. 1/4 C. 1/3 D. 3/8 E. 1/2

I chose A (1/2)(1/2)(1/2) = 1/8 (independent events) is this wrong?

There are 2 faces that are different... So either u consider the first tossing meaningless or u have to consider 3 times one side then 3 times the other side.

P = 1 * 1/2 * 1/2 = 1/4
or
P = P(Side1) + P(Side2) = 1/2 * 1/2 * 1/2 + 1/2 * 1/2 * 1/2 = 1/4

There are 2 faces that are different... So either u consider the first tossing meaningless or u have to consider 3 times one side then 3 times the other side.

P = 1 * 1/2 * 1/2 = 1/4 or P = P(Side1) + P(Side2) = 1/2 * 1/2 * 1/2 + 1/2 * 1/2 * 1/2 = 1/4

Got it! nice one

when tossed for the first time the probability that it will land on either side is one.

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