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Problem Solving - Inequality

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Manager
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Joined: 22 Mar 2010
Posts: 64
Followers: 1

Kudos [?]: 2 [0], given: 1

Problem Solving - Inequality [#permalink] New post 25 Jul 2010, 10:43
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (00:38) wrong based on 3 sessions
How many soultions are possible for the inequality, mod(x-3)+mod(x-4)<1 ?

a. 3
b. 4
c. 0
d. 6
e. Infinitely many
[Reveal] Spoiler: OA
CEO
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Status: Nothing comes easy: neither do I want.
Joined: 12 Oct 2009
Posts: 2793
Location: Malaysia
Concentration: Technology, Entrepreneurship
Schools: ISB '15 (M)
GMAT 1: 670 Q49 V31
GMAT 2: 710 Q50 V35
Followers: 178

Kudos [?]: 925 [0], given: 235

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Re: Problem Solving - Inequality [#permalink] New post 25 Jul 2010, 10:57
EnterMatrix wrote:
How many soultions are possible for the inequality, mod(x-3)+mod(x-4)<1 ?

a. 3
b. 4
c. 0
d. 6
e. Infinitely many


|x-3| + |x-4| < 1 ; take three cases

1.x>4

|x-3| + |x-4| < 1

x-3 +x-4 <1

x<4 not possible as we have assumed x>4

2.3<x<4

|x-3| + |x-4| < 1

x-3 + 4-x < 1 not possible

3. x<3

|x-3| + |x-4| < 1

3-x + 4-x <1

x> 3 not possible

hence 0 solution
Answer is C

PS: Make sure you check the answer against the domain. It should satisfy the domain.
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Re: Problem Solving - Inequality   [#permalink] 25 Jul 2010, 10:57
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