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ps - polygon

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VP
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13 Dec 2005, 13:26
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The vertices of an irregular pentagon are A, B, C, D, and E. If AB=5, BC=4, CD=3, DE=10, the length of AE could be which of the followings?

I. 5
II. 7
III. 23

A. I only
B. II only
C. III only
D. I and II only
E. I and II and III only
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13 Dec 2005, 13:36
E. Can be I, II or III.

0<AE<23

Is this correct?
Senior Manager
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13 Dec 2005, 14:33
I think it's E. There' no restriction for the side AE.
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VP
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13 Dec 2005, 14:38
rlevochkin wrote:
I think it's E. There' no restriction for the side AE.

If its closed polygon, one side cannot be bigger than "sum of all other four sides(22)".

Like in triangle, one side cannot be bigger than "sum of other two sides".
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13 Dec 2005, 15:31
Thanks, guys. I had no idea the same rule applies to polygons, too. Kaplan totally omits this point.
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13 Dec 2005, 16:24
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