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# PS-prep

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Director
Joined: 03 Sep 2006
Posts: 884
Followers: 6

Kudos [?]: 269 [0], given: 33

PS-prep [#permalink]  23 Jun 2007, 23:40
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Pl. exp.
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CIO
Joined: 09 Mar 2003
Posts: 464
Followers: 2

Kudos [?]: 34 [0], given: 0

First step, clear the root out of the bottom. You do that by multiplying the fraction by 1, using the root on the bottom over itself:

1/root(x+y) * root(x+y)/root(x+y) =

root(x+y)/(x+y)

Now you've got something to compare to.

The first one can't be right, because we don't know anything about xy, and the numerator is the same. If x and y are both 1, then x + y will be more than xy, if they're both 20, then the opposite is true.

The second one does seem to be right. I've tried a bunch of numbers, and it looks like root(x+y) is always less than root(x) + root(y).

The third one can't be right, because subtracting those two roots will be smaller than adding them, even inside the radical.

So two only.
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