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Q1 - M25

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Q1 - M25 [#permalink] New post 05 Jul 2009, 18:43
hi guys,

am referring to Q1 of the free M25 test - pls see below
OA is B but i chose E because i dont think S2 is sufficient

if x is 1, then I X-6 I should be = 5 and not >5
if x is -1, then I X-6 I > 5

Any thought, anyone?

------------------------------------------------------------------------
Is I X-6 I > 5?
1. X is an integer
2. X^2 < 1

Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient

Consider its geometric interpretation: is the distance between and 6 on the number line greater than 5?
Statement (1) is not sufficient by itself.
Statement (2) is sufficient by itself. is confined between -1 and 1 and thus is further than 5 units away from 6.


Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient
Consider its geometric interpretation: is the distance between and 6 on the number line greater than 5?

Statement (1) is not sufficient by itself.

Statement (2) is sufficient by itself.X is confined between -1 and 1 and thus is further than 5 units away from 6.

The correct answer is B.
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Re: Q1 - M25 [#permalink] New post 05 Jul 2009, 19:20
Quest: abs(x-6)>5 on solving
we get -1<x<1 , x>6 or x<-6
2) x2<1 also gives -1<x<1
So "B" is correct.
vikas
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Re: Q1 - M25 [#permalink] New post 05 Jul 2009, 20:43
panvik wrote:
Quest: abs(x-6)>5 on solving
we get -1<x<1 , x>6 or x<-6
2) x2<1 also gives -1<x<1
So "B" is correct.
vikas


sorry vikas, a bit slow here. still cant get you ..can you elaborate?
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Re: Q1 - M25 [#permalink] New post 06 Jul 2009, 20:06
gmattering666 wrote:
if x is 1, then I X-6 I should be = 5 and not >5


x cannot be 1, since the statement says that x^2 < 1, and not that x^2 < 1.

From the statement x^2 < 1, we can be certain that -1 < x < 1, and that x cannot be equal to either -1 or 1.
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Re: Q1 - M25 [#permalink] New post 09 Apr 2010, 12:53
I choose E too for this:

|X-6| > 5
Simplifing :
+Ve -ve
X-6 > 5 -X-6 > 5
X > 11 -X > -1 => X<1
Is this simplification wrong.
Stmt 1 is not sufficient
Stmt 2 says X^2 <1
This can be true only if X is a fraction so -1 < X< 1

Pls. clarify.
Re: Q1 - M25   [#permalink] 09 Apr 2010, 12:53
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