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Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
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question [#permalink]  05 Jun 2004, 12:08
can someone explain simplest way to do this?

What is the tens digit of 321^4?
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Re: question [#permalink]  05 Jun 2004, 21:40
321^4 = 21^4 = (441)^2 = 41^2 = 81 (mod 100)

10's digit = 8
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Re: question [#permalink]  06 Jun 2004, 05:10
Bhai wrote:
hallelujah1234 wrote:
321^4 = 21^4 = (441)^2 = 41^2 = 81 (mod 100)

10's digit = 8

What is mod 100 ?

mod 100 means to divide by 100 without having fraction part, so 321^4 mod 100 would give the remainder which is = 81.

Look at example:
5/2=2.5
5 mod 2 = 2 and 1 is remainder.
Re: question   [#permalink] 06 Jun 2004, 05:10
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