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Intern
Joined: 05 Jun 2009
Posts: 11
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Kudos [?]: 9 [1] , given: 6

Question [#permalink]  05 Jun 2009, 07:14
1
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Half of the pizza slice was cut in 4 bigger pieces and the remaining half into 5 smaller pieces. If Sally ate 3 of smaller pieces and one of the bigger pieces. What percent of the pizza is still in the box?
Intern
Joined: 04 Jun 2009
Posts: 48
Followers: 0

Kudos [?]: 3 [1] , given: 8

Re: Question [#permalink]  05 Jun 2009, 10:59
1
KUDOS
3/4 big pieces + 2/5 small pieces remain

(1/2 X 3/4) + (1/2 X 2/5)
=3/8 + 1/5
=15/40 + 8/40
=23/40
=57.5/100 or 57.5%

Last edited by jolt on 07 Jun 2009, 22:30, edited 1 time in total.
Manager
Joined: 01 May 2009
Posts: 116
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Kudos [?]: 27 [1] , given: 11

Re: Question [#permalink]  06 Jun 2009, 01:06
1
KUDOS
If the complete pizza is taken as a circle then
1 big piece contributes to 45 degrees
1 small piece contributes to 36 degrees

Remaining pizza is 2 small+3 big = 2*36+3*45=207 degrees

360 degrees ----- 100%

207 degrees -----57.5%
Manager
Joined: 03 Jun 2009
Posts: 50
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Kudos [?]: 3 [1] , given: 7

Re: Question [#permalink]  07 Jun 2009, 03:48
1
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Each Big piece constitutes to 12.5% of the total Pizza (Assuming Total Pizza to be 100%..Half of it is 50%...which is divided into 4 parts,each part of 50/4=12.5%)

Each Small Piece Constitutes to 10% of the total Pizza (Remaining Half of Pizza is 50%...which is divided into 5 parts,each part of 50/5=10%).

So Sally ate 3 of smaller pieces and one of the bigger pieces...implying she ate ( 3*10+12.5)% of the Pizza...ie...42.5%

Remaining Pizaaa in the box is 100-42.5%=57.5%
Re: Question   [#permalink] 07 Jun 2009, 03:48
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