Right Angled Triangle : Quant Question Archive [LOCKED]
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# Right Angled Triangle

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Director
Joined: 21 Sep 2004
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25 Dec 2004, 20:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

can somebody explain this one.
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Intern
Joined: 26 Dec 2004
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26 Dec 2004, 16:03
I am getting the answer as C: 9,900.

For point P, x & y can be chosen in 10*11 ways (10 possible x coord. values. 11 possible Y coordinate values. Once P is chosen, the y coordinate of R is fixed since PR is || to X axis. Therefore x coordinate for R can be one of (10 - 1) = 9 values. -1 because it cannot be same as P.

Similarly, Q has same X coordinate as P, but Y coordinate could be any of (11 - 1) values.

therefore total number of right angled triangles = 10*11*9*10 = 9,900
26 Dec 2004, 16:03
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