Find all School-related info fast with the new School-Specific MBA Forum
Learn more about the recent changes... close

It is currently 19 Jun 2013, 18:52
Customize  |  Hide

Search
Register
New posts
Unanswered

slope 3

  Question banks Downloads My Bookmarks Reviews  
  Oldest Best Reply
Search for:
 
Print view
First unread post
Author Message
TAGS:
Senior Manager
Senior Manager
Joined: 16 Apr 2009
Posts: 252
Schools: Ross
Followers: 1

Kudos [?]: 10 [0], given: 10

GMAT Tests User
slope 3 [#permalink] New post 14 Jul 2009, 14:09
00:00

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
The x-intercept of a line passing through points (5,-2) and (6,9) is _________________________
[Reveal] Spoiler:
57/11


please explain.
_________________

Keep trying no matter how hard it seems, it will get easier.

Senior Manager
Senior Manager
Joined: 25 Mar 2009
Posts: 305
Followers: 6

Kudos [?]: 41 [0], given: 6

GMAT Tests User
Re: slope 3 [#permalink] New post 14 Jul 2009, 14:16
You have to use a system of 2 equations. Plug in your given points into the formula for a line: y=mx+b

A: -2=m(5)+b
B: 9=m(6)+b

Subtract the bottom from the top:
-11 = -m
m = 11

Plug back into a to find the full equation:
A: -2=11(5)+b
b=-57

x-int. is where the line crosses the x-axis which means y=0. Plug this in:
y=11x-57
0=11x-57
x=57/11
Manager
Manager
Joined: 07 Apr 2009
Posts: 148
Followers: 1

Kudos [?]: 7 [0], given: 3

Re: slope 3 [#permalink] New post 15 Jul 2009, 08:07
given 2 points there is a direct eqn for a line

y-y2 = y2-y1/x2-x1 (x-x1)

using this , you get the eqn y+2 = 11(x-5)

for x-interecept you put y=0 and you get x = 57/11
Senior Manager
Senior Manager
Joined: 25 Mar 2009
Posts: 305
Followers: 6

Kudos [?]: 41 [0], given: 6

GMAT Tests User
Re: slope 3 [#permalink] New post 15 Jul 2009, 09:42
skpMatcha wrote:
given 2 points there is a direct eqn for a line

y-y2 = y2-y1/x2-x1 (x-x1)

using this , you get the eqn y+2 = 11(x-5)

for x-interecept you put y=0 and you get x = 57/11


I think your equation is wrong. I tried plugging in numbers and didn't get the correct equation. I believe the left side of the equation should be y - y1, not y - y2. Please confirm.
Manager
Manager
Joined: 07 Apr 2009
Posts: 148
Followers: 1

Kudos [?]: 7 [0], given: 3

Re: slope 3 [#permalink] New post 15 Jul 2009, 10:00
you are correct, you can use either of the points here but you need to stick with one point and use x & y coordinates of that point !

thanks for the correction!
Manager
Manager
Joined: 07 Apr 2009
Posts: 148
Followers: 1

Kudos [?]: 7 [0], given: 3

Re: slope 3 [#permalink] New post 15 Jul 2009, 10:07
y-y2= y2-y1/x2-x1(x-x2)

or

y-y1= y2-y1/x2-x1(x-x1)
Senior Manager
Senior Manager
Joined: 16 Apr 2009
Posts: 252
Schools: Ross
Followers: 1

Kudos [?]: 10 [0], given: 10

GMAT Tests User
Re: slope 3 [#permalink] New post 15 Jul 2009, 18:50
Thanks for the replies.
_________________

Keep trying no matter how hard it seems, it will get easier.

Re: slope 3   [#permalink] 15 Jul 2009, 18:50
    Similar topics Author Replies Last post
Similar
Topics:
 New posts Slope mirhaque 4 08 Jul 2005, 07:43
New posts What is the slope of the line with points (-3,4) and (4,-3)? desiguy 2 30 Nov 2005, 13:10
New posts Slope usman7 9 14 Dec 2006, 03:38
New posts a line has a slope of 3/4 and intersectws the point (12, bmwhype2 7 25 Sep 2007, 23:54
New posts slope vcbabu 4 31 May 2009, 10:10
Display posts from previous: Sort by

slope 3

  Question banks Downloads My Bookmarks Reviews  
Print view
First unread post

Moderators: VeritasPrepKarishma, Bunuel, IanStewart

Search for:


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.

Main navigation

GMAT Resources

Partners

MBA Resources

www.gmac.com|www.mba.com