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slope 3

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Senior Manager
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slope 3 [#permalink] New post 14 Jul 2009, 13:09
00:00
A
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Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
The x-intercept of a line passing through points (5,-2) and (6,9) is _________________________
[Reveal] Spoiler:
57/11


please explain.
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Keep trying no matter how hard it seems, it will get easier.

Senior Manager
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Re: slope 3 [#permalink] New post 14 Jul 2009, 13:16
You have to use a system of 2 equations. Plug in your given points into the formula for a line: y=mx+b

A: -2=m(5)+b
B: 9=m(6)+b

Subtract the bottom from the top:
-11 = -m
m = 11

Plug back into a to find the full equation:
A: -2=11(5)+b
b=-57

x-int. is where the line crosses the x-axis which means y=0. Plug this in:
y=11x-57
0=11x-57
x=57/11
Manager
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Re: slope 3 [#permalink] New post 15 Jul 2009, 07:07
given 2 points there is a direct eqn for a line

y-y2 = y2-y1/x2-x1 (x-x1)

using this , you get the eqn y+2 = 11(x-5)

for x-interecept you put y=0 and you get x = 57/11
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Re: slope 3 [#permalink] New post 15 Jul 2009, 08:42
skpMatcha wrote:
given 2 points there is a direct eqn for a line

y-y2 = y2-y1/x2-x1 (x-x1)

using this , you get the eqn y+2 = 11(x-5)

for x-interecept you put y=0 and you get x = 57/11


I think your equation is wrong. I tried plugging in numbers and didn't get the correct equation. I believe the left side of the equation should be y - y1, not y - y2. Please confirm.
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Re: slope 3 [#permalink] New post 15 Jul 2009, 09:00
you are correct, you can use either of the points here but you need to stick with one point and use x & y coordinates of that point !

thanks for the correction!
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Re: slope 3 [#permalink] New post 15 Jul 2009, 09:07
y-y2= y2-y1/x2-x1(x-x2)

or

y-y1= y2-y1/x2-x1(x-x1)
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Re: slope 3 [#permalink] New post 15 Jul 2009, 17:50
Thanks for the replies.
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Keep trying no matter how hard it seems, it will get easier.

Re: slope 3   [#permalink] 15 Jul 2009, 17:50
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