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Square root addition [#permalink]
02 Jan 2009, 18:42
Question Stats:
64% (02:44) correct
35% (00:33) wrong based on 7 sessions
Attachment:
Q1.JPG [ 10.17 KiB | Viewed 2385 times ]
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Re: Square root addition [#permalink]
02 Jan 2009, 19:16
That's what I answered, but that is not the correct answer according to the GMATprep.
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Re: Square root addition [#permalink]
03 Jan 2009, 16:10
9 + sqrt(80) + 9 -sqrt(80) + 2 sqrt (81-80)
=20
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Re: Square root addition [#permalink]
03 Jan 2009, 21:55
icandy, that is the correct answer, can you please explain your approach?
thanks
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Re: Square root addition [#permalink]
04 Jan 2009, 18:54
These are the concept that you need to know to solve this problem
(x+y)^2 = x^2 +2xy+y^2 sqrtX times sqrt Y = sqrt XY (a-b)(a+b) = a^2-b^2
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Re: Square root addition [#permalink]
05 Jan 2009, 17:55
(x+y)^2 = x^2+y^2+2xy 2*(9+sqrt(80))*(9-sqrt(80)=2*(81-80).
Rest of the explanation is clear from icandy.
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Re: Square root addition [#permalink]
10 Jan 2009, 11:46
squaring the term gives
9 + sqrt(80) + 9 - sqrt(80 + 2*(81 - 80) = 20
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Re: Square root addition [#permalink]
31 Aug 2009, 05:27
nagk78 wrote: squaring the term gives
9 + sqrt(80) + 9 - sqrt(80 + 2*(81 - 80) = 20 I understand the concept of x^2 + y^2 +2xy ... But can someone please explain how in the part 2xy they are getting 2*(81-80)? Because 2xy is 2 * ( sqrt(9) + sqrt(80) * sqrt(9) - sqrt(80)) ... or 2 * (sqrt(81)-sqrt(80)) i.e. not simply 81-80 **or is this one of those "find the closest approximation" questions.... and therefore should be spelled out in the question itself on the real GMAT?
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Re: Squares and Roots - PS [#permalink]
31 Aug 2009, 15:54
(sqrt{a} + sqrt{b})^2 = a + b + 2*sqrt{ab}
Here, a = 9 + sqrt{81} b = 9 - sqrt{81}
therefore, answer = 9 + [strike]sqrt{81}[/strike] + 9 - [strike]sqrt{81}[/strike] + 2*(81-80) = 9 + 9 + 2 = 20
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Re: Squares and Roots - PS [#permalink]
31 Aug 2009, 23:10
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i simply approximated i know .... 4 sqrt(5) = 4 * 2.2 ~ 8.8 on simplyfying (a+b)^ 2 .....i get major terms as 2*9+2*...... = hence ans is more than 18 hence 20
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Re: Squares and Roots - PS [#permalink]
15 Sep 2010, 00:30
im still not seeing the 81 and 80 here.....
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Re: Squares and Roots - PS [#permalink]
15 Sep 2010, 00:36
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Re: Squares and Roots - PS [#permalink]
15 Sep 2010, 02:26
Bunuel wrote: djslobo wrote: im still not seeing the 81 and 80 here.....  Hi and welcome to Gmat Club. Below is properly formated solution for this problem: You should know two properties: 1. (x+y)^2=x^2+2xy+y^2, ( (x-y)^2=x^2-2xy+y^2); 2. (x+y)(x-y)=x^2-y^2. (\sqrt{9+sqrt{80}}+\sqrt{9-\sqrt{80}})^2=(\sqrt{9+\sqrt{80}})^2+2(\sqrt{9+\sqrt{80}})(\sqrt{9-sqrt{80}})+(\sqrt{9-\sqrt{80}})^2==9+\sqrt{80}+2\sqrt{(9+\sqrt{80})(9-\sqrt{80})}+9-\sqrt{80}=18+2\sqrt{9^2-(\sqrt{80})^2}=18+2\sqrt{81-80}=18+2=20. Answer: E. Hope it helps. thnxs for the lucid explaination
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Re: Squares and Roots - PS
[#permalink]
15 Sep 2010, 02:26
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