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Hi all. I'm guessing this question must have some trick to solving it but i just dont know what it is. Please help. Thanks.

"If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location)"

Hi all. I'm guessing this question must have some trick to solving it but i just dont know what it is. Please help. Thanks.

"If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location)"

a. 6:22 b. 6:24 c. 6:27 d. 6:30 e. 6:32

go straight for 6:30...

since we have 7 and 7 in time and minuets, it must be 0 in the unit digit of minuets. so D.

2,880,717 - 2,880,000 = 717 (so far we are still at 6:27 p.m only at diffrent day)

minutes in 12 hours = 12* 60 = 720

720 - 717 = 3 (we are missing 3 minutes to move from 6:27 p.m to 6:27 a.m) so the exact time is 6:30 (D)

(*)

I wouldn't like to be a nitpicker but if I were a physicist I would have objected to that line of reasoning, after 5.5 years (2000/365) a slight adjustment will be needed in your clock to show the right time.

Last edited by KillerSquirrel on 17 Apr 2007, 19:16, edited 1 time in total.

Hi all. I'm guessing this question must have some trick to solving it but i just dont know what it is. Please help. Thanks.

"If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location)"

a. 6:22 b. 6:24 c. 6:27 d. 6:30 e. 6:32

go straight for 6:30...

since we have 7 and 7 in time and minuets, it must be 0 in the unit digit of minuets. so D.

Himalayan, could you explain in detail how you came up with 0 since the time and the minutes end in 7? thanks.

2,880,717 - 2,880,000 = 717 (so far we are still at 6:27 p.m only at diffrent day)

minutes in 12 hours = 12* 60 = 720

720 - 717 = 3 (we are missing 3 minutes to move from 6:27 p.m to 6:27 a.m) so the exact time is 6:30 (D)

(*)

I wouldn't like to be a nitpicker but if I were a physicist I would have objected to that line of reasoning, after 5.5 years (2000/365) a slight adjustment will be needed in your clock to show the right time.

Hi all. I'm guessing this question must have some trick to solving it but i just dont know what it is. Please help. Thanks.

"If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location)"

a. 6:22 b. 6:24 c. 6:27 d. 6:30 e. 6:32

go straight for 6:30...

since we have 7 and 7 in time and minuets, it must be 0 in the unit digit of minuets. so D.

Okay the answere to this question is D. But can you elaborate on how you came up with this answere.?

Hi all. I'm guessing this question must have some trick to solving it but i just dont know what it is. Please help. Thanks.

"If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location)"

a. 6:22 b. 6:24 c. 6:27 d. 6:30 e. 6:32

go straight for 6:30...

since we have 7 and 7 in time and minuets, it must be 0 in the unit digit of minuets. so D.

Okay the answere to this question is D. But can you elaborate on how you came up with this answere.?

Javed.

Cheers!

i think himalayan did it wrong.

ignore the big number. think in terms of 60 minutes. 12 hours * 60 = 720 minutes

720 - 717 = 3 minute difference. therefore, it is not a full twelve hours. so

6:27 + 3 minutes = 6:30

why addition? this is the logic behind it.
random numbers here
2-30 to 2-30 is 12 hours
2-30 to 2-27 is less than 12 hours
you gotta count forward from 2-30
not backwards from 2-27
time moves in 1 direction

Hi all. I'm guessing this question must have some trick to solving it but i just dont know what it is. Please help. Thanks.

"If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location)"

a. 6:22 b. 6:24 c. 6:27 d. 6:30 e. 6:32

i do not think you the question designed to calculate the whole lots of minuet and hours.

since it it 6:27 (i.e 27 minuets past 6 in the evening) and the question is asking what time is it 2,880,717 minuets before. just consider the unit digits of minuets. both are 7, so the unit digit of minuet should be 0. so pick D.

alternatively, what is the unit digit of the reminder if 239,494,847,595,94 is divided by 60? we do not need to divide the whole number by 60. since the unit digit of 60 is 0 and ther multiple of 60 has also unit digit as 0. so the unit digit of the reminder should also be 4.

excellent method of solving this problem. i fell into the trap and did it the loooong way. do you ever double check yourself when you use these lines of reasoning?

excellent method of solving this problem. i fell into the trap and did it the loooong way. do you ever double check yourself when you use these lines of reasoning?

for questions like this, i do not do cus for me these questions are just tricky. i do not do any calculations unless it is really required..