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# Triangle Problem DS Help

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Senior Manager
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14 Jul 2006, 17:11
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Help with this problem I found on paper test..
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Manager
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14 Jul 2006, 18:03
Statement (2) alone is not sufficient.

Statement (1) alone is sufficient.
Since we know the coordinates of p, we know the height of the triangle.
Using the law of sines, we are able to compute the length of RP. Hence we are able to compute the area of the triangle (which is RP/2 * h).

hence, (A).
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14 Jul 2006, 18:05
(A)

Given P's coordinates, we can calculate side of triangle as
2/3 = side*sin60
once we have side, area = sqrt(3)/4 *side^2
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14 Jul 2006, 18:12
(1) is enough,

if we know height of an equ. triangle, then area = h^2/rt(3).
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14 Jul 2006, 18:44
How do you get the area of triangle without using sine, cosine, etc. Those areas are not testable on GMAT
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15 Jul 2006, 00:26
jamesrwrightiii wrote:
How do you get the area of triangle without using sine, cosine, etc. Those areas are not testable on GMAT

I think you forgot to read "EQUILATERAL TRIANGLE". If you know the height of an equilateral triangle then you can find the area. In case of A height is 2/3 and this bisects the side RQ. Using pythagoras we get side = 4/3 (SQRT(1/3)) and area can be calculated.
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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