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Re: Tricky question [#permalink]
23 Nov 2011, 22:45
The area of the figure inside the circle seems to be composed of the half of the circle (because the cords form a right angle and therefore the hypotenuse of the triangle is the diameter of the circle cutting the middle of the circle) + the right triangle in the bottom left of the square. We should find its area. Area of 1/2 circle = PiR^2/2 = Pi/2 (as radius is 2/2=1) Area of triangle is 1/2 * 2 (hypotenuse) * 1 (hight to hypotenuse, which is a radius =1) =1 diff = Area of the Square - area of our figure = 2*2 - Pi/2 - 1 Ratio = diff / area of the square