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(165)^2 - (164)^2 =

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Manager
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(165)^2 - (164)^2 = [#permalink] New post 10 Mar 2012, 22:53
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

76% (01:45) correct 24% (01:17) wrong based on 84 sessions
(165)^2 - (164)^2 =

A. 1
B. 100
C. 229
D. 329
E. 349
[Reveal] Spoiler: OA
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SVP
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Posts: 1691
Location: United States (IN)
Concentration: Strategy, Technology
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Re: Subtracting Squared Numbers [#permalink] New post 10 Mar 2012, 22:55
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CLearly :

a^2 - b^2 = (a+b) * (a-b)

=> (165)^2 - (164)^2 = (165 + 164) * (165 - 164) = 329 * 1

Answer - D
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Manager
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Re: (165)^2 - (164)^2 = [#permalink] New post 10 Mar 2012, 23:07
Thanks!

... But what would you do if the problem were written more like this:

(165)^3 - (163)^3 =

or:

(165)^2 - (163)^3 =
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Re: (165)^2 - (164)^2 = [#permalink] New post 10 Mar 2012, 23:15
(165)^3 - (163)^3

You can use the formula a^3 - b^3

(165)^2 - (163)^3

Expand (163)^3 as (165 - 2)^3 to simplify further.
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Manager
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Re: (165)^2 - (164)^2 = [#permalink] New post 10 Mar 2012, 23:24
I think I'll have to go to YouTube or something for the ^2 x ^3, but I think I get the ^3 x ^3:

(165)^2 - (164)^2 = (165)^3 - (164)^3 = 329
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Re: (165)^2 - (164)^2 = [#permalink] New post 16 Apr 2012, 06:10
Stoneface wrote:
(165)^2 - (164)^2 =

A. 1
B. 100
C. 229
D. 329
E. 349


Difference between square of two consecutive numbers is = the sum of the of the two consecutive numbers

165+164 = 329

D
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Re: (165)^2 - (164)^2 = [#permalink] New post 27 Feb 2014, 20:32
Stoneface wrote:
(165)^2 - (164)^2 =

A. 1
B. 100
C. 229
D. 329
E. 349



Using the formula:

(a+1)^2 - a^2 = 2a+1

So, Answer = 164*2 + 1
= 328+1 = 329 = Answer = D
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Re: (165)^2 - (164)^2 =   [#permalink] 27 Feb 2014, 20:32
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