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Another Probability question

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Manager
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Joined: 28 Jul 2004
Posts: 136
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
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Kudos [?]: 36 [0], given: 2

Another Probability question [#permalink]

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New post 29 Aug 2010, 09:26
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HI, is there a simple way to solve the question below:

What is the probability of getting at least one heart in a 5-card hand dealt from a standard 52-card deck?

My approach was to calculate it as:

At least 1 heart = 1 - No Hearts, which implies

At least 1 heart = 1 -39/52 x 36/51 x 35/50 x 34/49 x 33/48

any simpler approach?

Thanks
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kris

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Kudos [?]: 30 [0], given: 0

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Re: Another Probability question [#permalink]

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New post 29 Aug 2010, 09:53
I guess that is the simplest approach for the question asking for "at least" xxxx

Probably you made a typo while posting your solution :

At least 1 heart = 1 -39/52 x 38/51 x 37/50 x 36/49 x 35/48

Thanks
Manager
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Joined: 28 Jul 2004
Posts: 136
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
Followers: 1

Kudos [?]: 36 [0], given: 2

Re: Another Probability question [#permalink]

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New post 29 Aug 2010, 10:05
yeh, I moved to 36 from 39 :)

anyway thanks.
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kris

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Re: Another Probability question [#permalink]

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New post 30 Aug 2010, 09:11
Hi krishan,

We can use this approach:

At least 1 heart = 1 -P (No Hearts) = 1- (39C5/52C5)

Will give same result.
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Re: Another Probability question [#permalink]

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New post 30 Aug 2010, 16:43
krishan wrote:
HI, is there a simple way to solve the question below:

What is the probability of getting at least one heart in a 5-card hand dealt from a standard 52-card deck?

My approach was to calculate it as:

At least 1 heart = 1 - No Hearts, which implies

At least 1 heart = 1 -39/52 x 36/51 x 35/50 x 34/49 x 33/48

any simpler approach?

Thanks



there isn't a simpler one!! :lol:

'at least 1' questions are best solve with the 1-no approach
Re: Another Probability question   [#permalink] 30 Aug 2010, 16:43
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Another Probability question

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